LRU算法是首先淘汰最长时间未被使用的页面,而LFU是先淘汰一定时间内被访问次数最少的页面,如果存在使用频度相同的多个项目,则移除最近最少使用(Least Recently Used)的项目. LFU在频度相同的时候与LRU类似. 146. LRU Cache 1.stl中list是双向链表,slist才是单向链表. rbegin():返回尾元素的逆向迭代器指针 end():返回尾元素之后位置的迭代器指针 https://www.cnblogs.com/Kobe10/p/5780095.html…

Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and put. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.put(…

Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1. set…

esign and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.set(k…

https://leetcode.com/problems/lru-cache/ Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exis…

题目: Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.…

LRU Cache Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise retu…

Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1. set…

Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.set(…

Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and put. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.put(…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典+双向链表 日期 题目地址:https://leetcode.com/problems/lru-cache/ 题目描述 Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operati…

设计和实现一个  LRU(最近最少使用)缓存 数据结构,使它应该支持以下操作: get 和 put .get(key) - 如果密钥存在于缓存中,则获取密钥的值(总是正数),否则返回 -1.put(key, value) - 如果密钥不存在,请设置或插入值.当缓存达到其容量时,它应该在插入新项目之前使最近最少使用的项目作废.后续:你是否可以在 O(1) 时间复杂度中进行两种操作?案例:LRUCache cache = new LRUCache( 2 /* 容量 */ );cache.put(1,…

原题地址 以前Leetcode的测试数据比较弱,单纯用链表做也能过,现在就不行了,大数据会超时.通常大家都是用map+双向链表做的. 我曾经尝试用C++的list容器来写,后来发现map没法保存list的iterator,总是报错,我也不知道为什么.后来只好手写双向链表,真是痛苦啊,一不小心就会出错.怪不得这道题是hard 代码: struct Node { int key; int val; Node *prev; Node *next; Node() : prev(NULL), next(N…

LeetCode题解: LRU Cache 缓存设计 2014年12月10日 08:54:16 邴越 阅读数 1101更多 分类专栏: LeetCode   版权声明:本文为博主原创文章,遵循CC 4.0 BY-SA版权协议,转载请附上原文出处链接和本声明. 本文链接:https://blog.csdn.net/leread/article/details/41841965 设计并实现最近最久未使用(Least Recently Used)缓存. 链接:https://oj.leetcode.c…

[题目] Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1…

Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1. set…

146. LRU缓存机制 运用你所掌握的数据结构,设计和实现一个 LRU (最近最少使用) 缓存机制.它应该支持以下操作: 获取数据 get 和 写入数据 put . 获取数据 get(key) - 如果密钥 (key) 存在于缓存中,则获取密钥的值(总是正数),否则返回 -1. 写入数据 put(key, value) - 如果密钥不存在,则写入其数据值.当缓存容量达到上限时,它应该在写入新数据之前删除最近最少使用的数据值,从而为新的数据值留出空间. 进阶: 你是否可以在 O(1) 时间复杂度…

Cache 缓存 1. 记忆 2. 空间有限 3. 钱包 - 储物柜 4. 类似背代码模板,O(n) 变 O(1)     LRU Cache 缓存替换算法 1. Least Recently Used(最近最少使⽤的淘汰掉) 2. Hash Table + Double LinkedList(哈希表 + 双向链表) 3. O(1) 查询 (cache只要查询第一个) 4. O(1) 修改.更新(同3:要是处理最中间的话就是O(n)了)   双向链表实现: LFU Cache 也记录元素出现的频…

目录 题目 思路 代码 复杂度分析 题目 146. LRU缓存机制 思路 利用双链表和HashMap来解题 看到链表题目,我们可以使用头尾结点可以更好进行链表操作和边界判断等 还需要使用size变量来存储双链表的当前长度 调用get,如果存在的话,我们可以调用将在双链表中的结点通过修改指针移动到第一个:如果调用put,我们先判断是否存在该结点,如果不存在,可直接将链接插入即可,同时size++,如果存在的话,先删除原来的结点,再将新结点push到头部即可 代码 class LRUCache {…

力扣链接:146. LRU 缓存机制 思路:哈希表 + 双向链表 为什么必须要用双向链表? 因为我们需要删除操作.删除一个节点不光要得到该节点本身的指针,也需要操作其前驱节点的指针,而双向链表才能支持直接查找前驱,保证操作的时间复杂度 O(1). 为什么要在链表中同时存储 key 和 val,而不是只存储 val? 当缓存容量已满,我们不仅仅要删除最后一个节点,还要把哈希表 中映射到该节点的 key 同时删除,而这个 key 只能由 节点得到.如果 节点结构中只存储 val,那么我们就无法得知…

题目简述: Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -…

题目大意:设计一个用于LRU cache算法的数据结构. 题目链接.关于LRU的基本知识可参考here 分析:为了保持cache的性能,使查找,插入,删除都有较高的性能,我们使用双向链表(std::list)和哈希表(std::unordered_map)作为cache的数据结构,因为: 双向链表插入删除效率高(单向链表插入和删除时,还要查找节点的前节点) 哈希表保存每个节点的地址,可以基本保证在O(1)时间内查找节点 具体实现细节: 越靠近链表头部,表示节点上次访问距离现在时间最短,尾部的节点…

最近在看Leveldb源码,里面用到LRU(Least Recently Used)缓存,所以自己动手来实现一下.LRU Cache通常实现方式为Hash Map + Double Linked List,我使用std::map来代替哈希表. 实现代码如下: #include <iostream> #include <map> #include <assert.h> using namespace std; // define double linked list no…

Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.set(…

Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.set(…

Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.set(…

Merge Sorted Array OJ: https://oj.leetcode.com/problems/merge-sorted-array/ Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space (size that is greater or equal to m + n) to hold add…

Description: Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise r…

LRU Cache 题目链接:https://oj.leetcode.com/problems/lru-cache/ Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the k…

设计并实现最近最久未使用(Least Recently Used)缓存. 题目描述: Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set. get(key) - Get the value (will always be positive) of the key if the key ex…