Description Advanced Cargo Movement, Ltd. uses trucks of different types. Some trucks are used for vegetable delivery, other for furniture, or for bricks. The company has its own code describing each type of a truck. The code is simply a string of ex…

题目链接:http://poj.org/problem?id=1789 大意: 不同字符串相同位置上不同字符的数目和是它们之间的差距.求衍生出全部字符串的最小差距. #include<stdio.h> #include<math.h> #include<algorithm> using namespace std; ; int cnt; int pre[MAXN]; ]; struct Edge { int from, to; int val; }edge[MAXN *…

题目链接:http://poj.org/problem?id=1789 Advanced Cargo Movement, Ltd. uses trucks of different types. Some trucks are used for vegetable delivery, other for furniture, or for bricks. The company has its own code describing each type of a truck. The code…

链接: http://poj.org/problem?id=1789 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=22010#problem/G Truck History Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 14950   Accepted: 5714 Description Advanced Cargo Movement, Ltd. uses…

题目链接:POJ 1789 Description Advanced Cargo Movement, Ltd. uses trucks of different types. Some trucks are used for vegetable delivery, other for furniture, or for bricks. The company has its own code describing each type of a truck. The code is simply…

Truck History 题目链接: http://acm.hust.edu.cn/vjudge/contest/124434#problem/E Description Advanced Cargo Movement, Ltd. uses trucks of different types. Some trucks are used for vegetable delivery, other for furniture, or for bricks. The company has its…

模板题 题目:http://poj.org/problem?id=1789 题意:有n个型号,每个型号有7个字母代表其型号,每个型号之间的差异是他们字符串中对应字母不同的个数d[ta,tb]代表a,b之间的差异数问1/Σ(to,td)d(to,td)最大值 prime: #include <iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<stack>…

Truck History Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 21518   Accepted: 8367 Description Advanced Cargo Movement, Ltd. uses trucks of different types. Some trucks are used for vegetable delivery, other for furniture, or for brick…

题目传送门 题意:给出n个长度为7的字符串,一个字符串到另一个的距离为不同的字符数,问所有连通的最小代价是多少 分析:Kuskal/Prim: 先用并查集做,简单好写,然而效率并不高,稠密图应该用Prim而且要用邻接矩阵,邻接表的效率也不高.裸题但题目有点坑爹:( Kruskal: #include <cstdio> #include <cstring> #include <string> #include <algorithm> #include <…

 POJ 1789 -- Truck History Prim求分母的最小.即求最小生成树 #include<iostream> #include<cstring> #include<algorithm> using namespace std; + ; ; int n;//有几个卡车 ]; int d[maxn];//记录编号的数值 int Edge[maxn][maxn]; int dist[maxn]; void prim() { ; //加入源点 dist[]…