题目:House Robber You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected a…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

动态规划 https://blog.csdn.net/so_geili/article/details/53639920 最长公共子序列 https://blog.csdn.net/so_geili/article/details/53737001#comments…

public class Solution { public int Rob(int[] nums) { ; ; ; k < nums.Length; k++) { int tmp = i; i = nums[k] + e; e = Math.Max(tmp, e); } return Math.Max(i, e); } } https://leetcode.com/problems/house-robber/#/description /* 你是一个专业强盗,并计划沿街去盗窃每一个住户.每个房…

你是一个专业的小偷,计划偷窃沿街的房屋.每间房内都藏有一定的现金,影响你偷窃的唯一制约因素就是相邻的房屋装有相互连通的防盗系统,如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警. 给定一个代表每个房屋存放金额的非负整数数组,计算你在不触动警报装置的情况下,能够偷窃到的最高金额. 示例 1: 输入: [1,2,3,1]输出: 4解释: 偷窃 1 号房屋 (金额 = 1) ,然后偷窃 3 号房屋 (金额 = 3).  偷窃到的最高金额 = 1 + 3 = 4 .示例 2: 输入: [2,7,9…

问题描述: 你是一个专业的小偷,计划偷窃沿街的房屋.每间房内都藏有一定的现金,影响你偷窃的唯一制约因素就是相邻的房屋装有相互连通的防盗系统,如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警. 给定一个代表每个房屋存放金额的非负整数数组,计算你 不触动警报装置的情况下 ,一夜之内能够偷窃到的最高金额.   解析: 首先考虑只有一间房屋情况.当只有一间房屋,偷窃最高金额即是这间房屋金额   当有两间房屋时,偷窃最大金额为两间房屋中的最大值   当房屋数在2间以上时,假设房屋k被偷,则前k间房屋…

题目 You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will au…

动态规划(DP)算法     动态规划是运筹学的一个分支,是求解决策过程最优化的数学方法.利用各个阶段之间的关系,逐个求解,最终求得全局最优解,需要确认原问题与子问题.动态规划状态.边界状态.边界状态结值.状态转移方程. 一.爬楼梯leetcode70: You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how m…

子集和问题:给定一组数和一个值,从这组数中选出若干个数使其和为给定的值.这是个NPC问题. 1.https://leetcode.com/problems/counting-bits/#/solutions 给定一非负Integer num,求[0,num]每个数的二进制形式中1的个数  f[num+1]. 解法:可用最朴素的方法逐个求,但其实有规律: f[i] = f[i / ] + i % 或  f[i] = f[i&(i-)] + ; 2.Single Number:一组Integer类型…

参考https://blog.csdn.net/libosbo/article/details/80038549 动态规划是求解决策过程最优化的数学方法.利用各个阶段之间的关系,逐个求解,最终求得全局最优解,需要确认原问题与子问题.动态规划状态.边界状态.边界状态结值.状态转移方程. 以下每个例题,注意分析迭代关系是怎么找到的. 一.爬楼梯leetcode70: You are climbing a stair case. It takes n steps to reach to the top…

""" On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start f…

大家好!我是 Johngo 呀! 和大家一起刷题不快不慢,没想到已经进行到了第二阶段,「动态规划」这部分题目很难,而且很不容易理解,目前我的题目做了一半,凭着之前对于「动态规划」的理解和最近做的题目做一个阶段性的总结!这篇文章其实是我之前写过的一篇,然后现在拿来再做一个润色. 「动态规划」看这篇我...保证可以! 目标:给小白以及没有明确思路的同学一个指引! 拍胸脯保证:读完这篇文章,对于大多数的动态规划的思维逻辑能有一个质的提升. 本文较长,建议先收藏,或者直接到 GitHub 中下载文档(h…