上图论课的时候无意之间看到了这个,然后花了几天的时间学习了下,接下来做一个总结. 一般斯坦纳树问题是指(来自百度百科): 斯坦纳树问题是组合优化问题,与最小生成树相似,是最短网络的一种.最小生成树是在给定的点集和边中寻求最短网络使所有点连通.而最小斯坦纳树允许在给定点外增加额外的点,使生成的最短网络开销最小. 然后听说已经被证明为是NP问题了,在ACM竞赛中我们不研究这个,我们研究更简单一些的问题. 对于图G(V,E),其中V表示图中点集,E表示图中边集.设A是V的某个子集,求至少包含A中所有点…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2489 Problem Description For a tree, which nodes and edges are all weighted, the ratio of it is calculated according to the following equation. Given a complete graph of n nodes with all nodes and edges…

hdu2489 Minimal Ratio Tree 题意:一个 至多  n=15 的 完全图 ,求 含有 m 个节点的树 使 边权和 除 点权和 最小 题解:枚举 m 个 点 ,然后 求 最小生成树 自己粗心....WA 了 好多次……(233333 ) #include <iostream> #include <cstring> #include <cstdio> #include <cmath> #include <algorithm> #…

Minimal Ratio Tree Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 12   Accepted Submission(s) : 7 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description For a tree, which n…

Minimal Ratio Tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) [Problem Description] For a tree, which nodes and edges are all weighted, the ratio of it is calculated according to the following equation.Given a…

Minimal Ratio Tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2180    Accepted Submission(s): 630 Problem Description For a tree, which nodes and edges are all weighted, the ratio of it is…

Description For a tree, which nodes and edges are all weighted, the ratio of it is calculated according to the following equation. Given a complete graph of n nodes with all nodes and edges weighted, your task is to find a tree, which is a sub-graph…

Minimal Ratio Tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2382    Accepted Submission(s): 709 Problem Description For a tree, which nodes and edges are all weighted, the ratio of it is…

Minimal Ratio Tree HDU - 2489 暴力枚举点,然后跑最小生成树得到这些点时的最小边权之和. 由于枚举的时候本来就是按照字典序的,不需要额外判. 错误原因:要求输出的结尾不能有空格. #include<cstdio> #include<cstring> #include<vector> using namespace std; ],ok2[]; ]; int num,n,m; ],b[][]; vector<int> vec; dou…

Minimal Ratio Tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3345    Accepted Submission(s): 1019 Problem Description For a tree, which nodes and edges are all weighted, the ratio of it i…