任意一堆移动过后的石子都是整数x的倍数, 那么石子总数显然也应该是x的倍数, 换句话说,x必为石子数总和的一个质因子. 题目要求移动次数尽量小,那么x也应该尽量小. 所以选择石子数总和的最小质因子. 对每堆石子数进行取模运算即可知道每堆石子需要移走或增加多少石子. 然后就可以开始模拟了. 把取模后的石子数进行从大到小的排序并求出取模后的石子总数, 然后求出可以组成x的个数. 用大石子堆到小石子堆去减这些x,在累加起来,即得到最少移动次数. #include <iostream> #includ…

2014816 机型:红米2A高配版 设备型号:2014816 CPU:高通 线刷:fastboot平台 http://192.168.7.118/MesReports/Reports/CuttingForecast.aspx?Factory_Cd=YMG&moNo=S16C15789BODY1-001&site=YMG --刷机教程http://www.netded.com/a/jingpinshouji/2015/1007/30942.html http://www.miui.com/…

A New Stone Game Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 5769   Accepted: 3158 Description Alice and Bob decide to play a new stone game.At the beginning of the game they pick n(1<=n<=10) piles of stones in a line. Alice and Bob…

1.题目: 1180. Stone Game Time limit: 1.0 secondMemory limit: 64 MB Two Nikifors play a funny game. There is a heap of N stones in front of them. Both Nikifors in turns take some stones from the heap. One may take any number of stones with the only cond…

问题一 sed编辑命令:[sed -i 's/a/b/g' test.txt]   报错:sed: 1: "test.txt": undefined label 'est.txt'   解决方案:增加一个备份的追加名[sed -i '.bak' 's/a/b/g' test.txt]   原因:mac强制要求备份,否则报错 当然可以不使用其他备份名字,只是用’',就可以只保留一份 sed -i ‘’ ’s/a/b/g’ test.txt   问题二 sed追加命令:[sed -i ''…

Zhuge Liang's Stone Sentinel Maze Time Limit: 10000/4000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 385    Accepted Submission(s): 106 Problem Description Zhuge Liang was a chancellor of the state of Shu Han dur…

A New Stone Game Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 5453   Accepted: 2989 Description Alice and Bob decide to play a new stone game.At the beginning of the game they pick n(1<=n<=10) piles of stones in a line. Alice and Bob…

F - Again Stone Game Time Limit:2000MS     Memory Limit:32768KB     64bit IO Format:%lld & %llu Submit Status Description Alice and Bob are playing a stone game. Initially there are n piles of stones and each pile contains some stone. Alice stars the…

Lifting the Stone Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1115 Description There are many secret openings in the floor which are covered by a big heavy stone. When the stone is lifted up…

http://poj.org/problem?id=1740 题目大意就是,对于n堆石子,每堆若干个,两人轮流操作,每次操作分两步,第一步从某堆中去掉至少一个,第二步(可省略)把该堆剩余石子的一部分分给其它的某些堆.最后谁无子可取即输. 看了题解感觉太神了. 首先我们来分析: 当只有一堆时,先手必胜,直接一次取完即可 当有两堆时,分两种情况,一是两堆相同时,先手必输,因为无论先手怎样取,后手总有办法再次平衡两堆:而是两堆不同时,先手必胜,因为先手总有办法先平衡两堆,然后就像一的情况. 当有三堆时…