hdu 5904 LCIS dp

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LCIS Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Problem Description Alex has two sequences a1,a2,...,an and b1,b2,...,bm. He wants find a longest common subsequence that consists of consecutive values in incre…

HDU 5904 - LCIS (BestCoder Round #87)

HDU 5904 - LCIS [ DP ] BestCoder Round #87 题意: 给定两个序列,求它们的最长公共递增子序列的长度, 并且这个子序列的值是连续的分析: 状态转移方程式: dp[a[i]] = max(dp[a[i]], dp[a[i]-1] + 1); 发现其实可以简化为 dp[a[i]] = dp[a[i]-1] + 1:因为计算过程中dp[a[i]]不会降低对两个序列都求一遍,然后取两者最小值的最大值 #include <cstdio> #include…

HDU 5904 LCIS （最长公共上升序列）

传送门 Description Alex has two sequences a1,a2,...,an and b1,b2,...,bm. He wants find a longest common subsequence that consists of consecutive values in increasing order. Input There are multiple test cases. The first line of input contains an integer…

HDU 5904 LCIS

$dp$. 这题的突破口在于要求数字是连续的. 可以分别记录两个串以某个数字为结尾的最长上升长度,然后枚举一下以哪个数字为结尾就可以得到答案了. 因为$case$有点多,不能每次$memset$,额外开一个数组记录一下这组$case$中数字有没有出现过. #pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cm…

hdu 4123 树形DP+RMQ

http://acm.hdu.edu.cn/showproblem.php? pid=4123 Problem Description Bob wants to hold a race to encourage people to do sports. He has got trouble in choosing the route. There are N houses and N - 1 roads in his village. Each road connects two houses,…

hdu 4507 数位dp（求和，求平方和）

http://acm.hdu.edu.cn/showproblem.php?pid=4507 Problem Description 单身! 依旧单身! 吉哥依旧单身! DS级码农吉哥依旧单身! 所以.他生平最恨情人节,无论是214还是77.他都讨厌! 吉哥观察了214和77这两个数,发现: 2+1+4=7 7+7=7*2 77=7*11 终于,他发现原来这一切归根究竟都是由于和7有关!所以,他如今甚至讨厌一切和7有关的数. 什么样的数和7有关呢? 假设一个整数符合以下3个条件之中的一个.那么我…

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http://acm.hdu.edu.cn/showproblem.php?pid=3709 Problem Description A balanced number is a non-negative integer that can be balanced if a pivot is placed at some digit. More specifically, imagine each digit as a box with weight indicated by the digit.…