B. Continued Fractions time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A continued fraction of height n is a fraction of form . You are given two rational numbers, one is represented as  a…
A continued fraction of height n is a fraction of form . You are given two rational numbers, one is represented as  and the other one is represented as a finite fraction of height n. Check if they are equal. Input The first line contains two space-se…
ACM思维题训练集合 To confuse the opponents, the Galactic Empire represents fractions in an unusual format. The fractions are represented as two sets of integers. The product of numbers from the first set gives the fraction numerator, the product of numbers…
http://codeforces.com/problemset/problem/305/B 题意:就是判断 p / q 等不等于那条式子算出来的值. 思路:一开始看到 1e18 的数据想了好久还是不会,暴力了一发显然错了.后来倒着想,就是 p / q(整除)的值一定要大于等于 a[i],否则就不行,每次判断完之后更新 p / q 即可,注意要判分母是否为0,因为这个RE了一次.思维僵化很严重,如果活跃一点估计很快就想出来了.吸取教训. #include <cstdio> #include &…
题意:丑数就是质因子只有2,3,5 ,7,的数,另外1也是丑数.求第n(1=<n<=5842)个丑数,n=0,结束. 思路:.3.5或者7的结果(1除外).那么,现在最主要的问题是如何排序,而且使得求得数不重复. <阶梯式上升>:从ans[1]=1,p1=1,p2=1,p3=1,p4=1,分别用2,3,5,7乘ans[px],得到一个v(min),这个v就是下一个ans, 同时,对应的px++; 技巧:因为题目中是多组输入,所以没必要没输入一个数就把程序跑一遍,而且n有上限,索性用…
任意门:http://codeforces.com/gym/100641/attachments Con + tin/(ued + Frac/tions) Time Limit: 3000/1000 MS (Java/Others)     Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 217     Accepted Submission(s): 27 Description The (simple) contin…
最大的数 时间限制:1000 ms  |           内存限制:65535 KB 难度:3 描述 小明和小红在打赌说自己数学学的好,于是小花就给他们出题了,考考他们谁NB,题目是这样的给你N个数 在这n个数之间添加N-1个*或+,使结果最大,但不可以打乱原顺序,请得出这个结果 如 1 3 5 结果是(1+3)*5=20:最大 可以添加若干个括号,但一定要保证配对,但是每两个数之间只可能有一个*或+ 数列最前和最后不应有+或乘 小明想赢小红但是他比较笨,请你帮帮他 输入 多组测试数据以EO…
Amr and Pins time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Amr loves Geometry. One day he came up with a very interesting problem. Amr has a circle of radius r and center in point (x, y).…
Problem Description ztr loves research Math.One day,He thought about the "Lower Edition" of triangle equation set.Such as n=x2−y2. He wanted to know that ,for a given number n,is there a positive integer solutions? Input There are T test cases.…
困难,.,真,,,不是太困难 的问题是,有一个矩阵运算优化 您有权发言权N*K矩阵A给K*N矩阵B(1<=N<=1000 && 1=<K<=6).他们拿起了第一次骑马C矩阵,再算上C^(N*N) 当于 ABABABABABABAB...=(AB)^(N*N) 不如 A(BA)^(N*N-1)B 由于BA乘得K*K的矩阵,K是比較小的 #include <cstdio> #include <cstdlib> #include <cstri…