$$\bex \sen{\pi}_{L^{s,\infty}(0,T;L^{q,\infty}(\bbR^3))} \leq \ve_*, \eex$$ with $$\bex \frac{2}{s}+\frac{3}{q}=2,\quad \frac{5}{2}\leq q\leq 3. \eex$$ $$\bex \sen{\n \pi}_{L^{s,\infty}(0,T;L^{q,\infty}(\bbR^3))} \leq \ve_*, \eex$$ with $$\bex \frac…

$$\bex \sen{\pi}_{L^{s,\infty}(0,T;L^{q,\infty}(\bbR^3))} \leq \ve_*, \eex$$ with $$\bex \frac{2}{s}+\frac{3}{q}=2,\quad 3< q<\infty. \eex$$ 这篇文章有错误...可惜了. 暂时无法修正.…

$$\bex \bbu\in L^p(0,T;L^{q,\infty}),\quad \frac{2}{p}+\frac{3}{q}=1,\quad 3<q\leq\infty. \eex$$ or $$\bex \sen{\bbu}_{L^{p,\infty}(0,T;L^{q,\infty})}\leq \ve,\quad \frac{2}{p}+\frac{3}{q}=1,\quad 3<q\leq \infty \eex$$…

$$\bex \int_0^T\frac{\sen{\bbu}_{L^{q,\infty}}^p}{\ve+\ln \sex{e+\sen{\bbu}_{L^\infty}}}\rd s<\infty. \eex$$…

$$\bex \sen{\pi}_{L^{s,\infty}(0,T;L^{q,\infty}(\bbR^3))} +\sen{{\bf b}}_{L^{\gamma,\infty}(0,T;L^{\tt,\infty}(\bbR^3))}^2\leq \ve_*, \eex$$ with $$\bex \frac{2}{s}+\frac{3}{q}=2,\quad \frac{5}{2}\leq q\leq 3; \eex$$ $$\bex \frac{2}{\gamma}+\frac{3}{…

$$\bex \bbu\in L^{p,r}(0,T;L^{q,\infty}(\bbR^3)),\quad\frac{2}{p}+\frac{3}{q}=1,\quad 3<q<\infty,\quad 2<p<r<\infty, \eex$$ or $$\bex \sen{\bbu}_{L^{p,\infty}(0,T;L^{q,\infty}(\bbR^3))}\leq \ve,\quad \frac{2}{p}+\frac{3}{q}=1,\quad 3<q&l…

$$\bex \p_3\pi\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=2,\quad 3\leq q\leq \infty. \eex$$…

$$\bex u_3\in L^\infty(0,T;L^\frac{10}{3}(\bbR^3)). \eex$$…

$$\bex u_3\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=\frac{3}{4}+\frac{1}{2q},\quad \frac{10}{3}<q\leq\infty. \eex$$…

$$\bex u_3\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=\frac{2}{3}+\frac{2}{3q},\quad \frac{7}{2}<q\leq \infty. \eex$$…

$$\bex u_3\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=\frac{5}{8},\quad \frac{24}{5}<q\leq \infty. \eex$$…

$$\bex u_3\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=\frac{1}{2},\quad 6< q\leq \infty. \eex$$…

$$\bex \p_3\bbu\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=2,\quad \frac{27}{16}\leq q\leq \frac{5}{2}. \eex$$…

$$\bex \p_3\bbu\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=2,\quad \frac{9}{4}\leq q\leq 3. \eex$$…

$$\bex \p_3\bbu\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=\frac{3}{2},\quad 2\leq q\leq \infty. \eex$$…

NSE, $\bbu$ [Papers]NSE, $u$, Lorentz space [Sohr, JEE, 2001] [Papers]NSE, $u$, Lorentz space [Bjorland-Vasseur, JMFM, 2011] [Papers]NSE, $u$, Lorentz space [Bosia-Pata-Robinson, JMFM, 2014] NSE, $u_3$ [Papers]NSE, $u_3$, Lebesgue space [NNP, QM, 200…

$$\bex \p_3\pi\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=2,\quad \frac{3}{2}\leq q\leq 3. \eex$$…

$$\bex \p_3\pi\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=\frac{12}{7},\quad \frac{12}{7}\leq q\leq 4. \eex$$…

$$\bex \n u_3\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=\frac{3}{2},\quad 2\leq q\leq \infty. \eex$$…

http://dl.acm.org/citation.cfm?id=2398426   http://dl.acm.org/citation.cfm?id=2396825   http://dl.acm.org/citation.cfm?id=2396826   http://dl.acm.org/citation.cfm?id=2398494   http://dl.acm.org/citation.cfm?id=2398557   http://dl.acm.org/citation.cfm…

Accepted Papers by Session Research Session RT01: Social and Graphs 1Tuesday 10:20 am–12:00 pm | Level 3 – Ballroom AChair: Tanya Berger-Wolf Efficient Algorithms for Public-Private Social NetworksFlavio Chierichetti,Sapienza University of Rome; Ales…

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作者:我爱机器学习原文链接:SIGKDD历年Best Papers SIGKDD(Data Mining)(1997-2016) 年份 标题 一作 一作单位 2016 FRAUDAR: Bounding Graph Fraud in the Face of Camouflage Bryan Hooi Carnegie Mellon University 2015 Efficient Algorithms for Public-Private Social Networks Flavio Chie…

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错误信息中的PermGen space的全称是Permanent Generation space,是指内存的永久保存区域.还没有弄明白PermGen space是属于非堆内存,还是就是非堆内存,但至少是属于了.XX:MaxPermSize设置过小会导致java.lang.OutOfMemoryError: PermGen space 就是内存益出. 用于存放Class和Meta的信息,Class在被 Load的时候被放入PermGen space区域,它和和存放Instance的Heap区域不…