UVA 674_Coin Change

【UVA 674_Coin Change】的更多相关文章

题意: 给定一个数,求用1,5,10,25,50有多少种组合方式. 分析: 简单计数dp,dp[i][j]表示由前i+1个元素组成j的种数,注意dp[i][0]初始化为1,因为一个元素也不选的方法总是有一种. 代码: #include<iostream> #include<cstring> using namespace std; const int maxn = 7500; long long dp[10][maxn + 5]; int main (void) { int a[5…

UVA 674 Coin Change（dp）

UVA 674 Coin Change 解题报告题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=87730#problem/E 题目: Suppose there are 5 types of coins: 50-cent, 25-cent, 10-cent, 5-cent, and 1-cent. We want to make changes with these coins for a given amount o…

UVA.674 Coin Change (DP 完全背包)

UVA.674 Coin Change (DP) 题意分析有5种硬币, 面值分别为1.5.10.25.50,现在给出金额,问可以用多少种方式组成该面值. 每种硬币的数量是无限的.典型完全背包. 状态转移方程 dp[j+c[i]] = dp[j] + dp[j+c[i]] 代码总览 /* Title:UVA.674 Author:pengwill Date:2017-2-16 */ #include <iostream> #include <cstdio> #include <…

UVA 674 Coin Change （DP）

Suppose there are 5 types of coins: 50-cent, 25-cent, 10-cent, 5-cent, and 1-cent. We want to make changes with these coins for a given amount of money. For example, if we have 11 cents, then we can make changes with one 10-cent coin and one 1-cent c…

Coin Change UVA

Suppose there are 5 types of coins: 50-cent, 25-cent, 10-cent, 5-cent, and 1-cent. We want to makechanges with these coins for a given amount of money.For example, if we have 11 cents, then we can make changes with one 10-cent coin and one 1-centcoin…

UVa 674 Coin Change【记忆化搜索】

题意:给出1,5,10,25,50五种硬币,再给出n,问有多少种不同的方案能够凑齐n 自己写的时候写出来方案数老是更少(用的一维的) 后来搜题解发现,要用二维的来写 http://blog.csdn.net/keshuai19940722/article/details/11025971 这一篇说的是会有面值的重复问题,还不是很理解还有就是一个预处理的问题, 看了题解之后再自己写,很习惯的把处理dp数组写到while循环里面,一直tle 后来看到这篇题解 http://www.cnblogs.…

UVa 674: Coin Change

动态规划题.对于1,5,10,25,50五种币值的硬币,编号为0~4,存入数组cent中.数组iWay的元素iWay[k][i]表示仅使用0~i的硬币凑出k分钱的方法数,按是否使用编号为i的硬币分类,可得到状态转移方程iWay[k][i]=iWay[k][i-1]+iWay[k-cent[i]][i]. 一个优化的方法:分析可知取15,16,17,18,19分钱的方法数是相同的,因为它们的差距只在于1分的硬币数目.故iWay[k][i]=iWay[k/5*5][i].这个式子可以稍微节省程序运行…