Hopscotch Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 2113   Accepted: 1514 Description The cows play the child's game of hopscotch in a non-traditional way. Instead of a linear set of numbered boxes into which to hop, the cows creat…

原题链接:http://poj.org/problem?id=3050 (一些文字过会儿再说现在有事儿) #include <cstdio> #include <set> using namespace std; int a[7][7],dx[]={317,0,0,1,-1},dy[]={318,1,-1,0,0};//4个方向 set<int>ans;//答案 void dfs(int x,int y,int d,int n)//x和y是坐标.d是深度,也就是长度.n…

思路: 水题. 实现: #include <iostream> #include <cstdio> #include <set> using namespace std; ][]; ] = { , , , - }; ] = { , , -, }; ]; ]; void dfs(int x, int y, int d) { ) { ; ; i < ; i++) { tmp += now[i]; ) tmp *= ; } vis[tmp] = true; return…

POJ2718 Smallest Difference Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6509   Accepted: 1773 Description Given a number of distinct decimal digits, you can form one integer by choosing a non-empty subset of these digits and writing…

-->Hopscotch 这接写中文了 Descriptions: 奶牛们以一种独特的方式玩孩子们的跳房子游戏. 奶牛们创造了一个5x5的格子 他们熟练地跳上其中的一个格子,可以前后左右地跳(不能对角)到另一个格子上.之后继续跳(可能跳到曾经跳过的格子上). 他们总共跳5次,路径可以看作一个六位数 (准确的说是一个六位序列,如000201是可行的). 请你找到这样的六位序列的总数 Input * 输入一个5x5的地图 Output * 所有可能六位序列的总数 Sample Input 1 1 1…

River Hopscotch Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 11031   Accepted: 4737 Description Every year the cows hold an event featuring a peculiar version of hopscotch that involves carefully jumping from rock to rock in a river.…

River Hopscotch Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 9263 Accepted: 3994 Description Every year the cows hold an event featuring a peculiar version of hopscotch that involves carefully jumping from rock to rock in a river. The e…

River Hopscotch Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 5193 Accepted: 2260 Description Every year the cows hold an event featuring a peculiar version of hopscotch that involves carefully jumping from rock to rock in a river. The e…

POJ3285 River Hopscotch 此题是大白P142页(即POJ2456)的一个变形题,典型的最大化最小值问题. C(x)表示要求的最小距离为X时,此时需要删除的石子.二分枚举X,直到找到最大的X,由于c(x)=m时满足题意,所以最后输出的是ub-1或者lb(lb==ub-1 注意相邻距离小于x的要删除(此处不是小于等于),对于相邻的距离小于x的两个石子,当删除其中一个后,又会产生其他的相邻的石子,直接计数不好计数,不妨用两个标记last,cur,其中last表示上一个石子,cur…

Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 5473   Accepted: 2379 Description Every year the cows hold an event featuring a peculiar version of hopscotch that involves carefully jumping from rock to rock in a river. The excitement ta…