229 Majority Element II 求众数 II】的更多相关文章

题目描述 给定一个大小为 n 的数组,找到其中的众数.众数是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素. 你可以假设数组是非空的,并且给定的数组总是存在众数. 示例 1: 输入: [3,2,3] 输出: 3 示例 2: 输入: [2,2,1,1,1,2,2] 输出: 2 思路 思路一: 利用哈希表的映射,储存数组中的数字以及它们出现的次数,当众数出现时,返回这个数字. 思路二: 因为众数是出现次数大于n/2的数字,所以排序之后中间的那个数字一定是众数.即nums[n/2]为众数.但是在计算比…
网址:https://leetcode.com/problems/majority-element-ii/ 参考:https://blog.csdn.net/u014248127/article/details/79230221 摩尔投票算法( Boyer-Moore Voting Algorithm) class Solution { public: vector<int> majorityElement(vector<int>& nums) { vector<in…
给定一个大小为 n 的数组,找出其中所有出现超过 ⌊ n/3 ⌋ 次的元素. 你的算法应该在O(1)空间中以线性时间运行. 详见:https://leetcode.com/problems/majority-element-ii/description/ 摩尔投票法 Moore Voting Java实现: class Solution { public List<Integer> majorityElement(int[] nums) { List<Integer> res=ne…
169. Majority Element 求超过数组个数一半的数 可以使用hash解决,时间复杂度为O(n),但空间复杂度也为O(n) class Solution { public: int majorityElement(vector<int>& nums) { unordered_map<int,int> count; int n=nums.size(); ;i<n;i++){ ) return nums[i]; } ; } }; 使用投票法,时间复杂度为O(…
Q: 给定一个大小为 n 的数组,找出其中所有出现超过 ⌊ n/3 ⌋ 次的元素. 说明: 要求算法的时间复杂度为 O(n),空间复杂度为 O(1). 示例 1: 输入: [3,2,3] 输出: [3] 示例 2: 输入: [1,1,1,3,3,2,2,2] 输出: [1,2] A: 一个叫摩尔投票的算法,可以在一次遍历中找出一个数组中的众数(出现次数一半以上的).通过设置一个计数器和当前'众数',若再遇到当前众数计数器加1,遇到其他数字减一,计数器归零时更新当前众数.巧妙之处是每次归零时前面划…
229. 求众数 II 给定一个大小为 n 的数组,找出其中所有出现超过 ⌊ n/3 ⌋ 次的元素. 说明: 要求算法的时间复杂度为 O(n),空间复杂度为 O(1). 示例 1: 输入: [3,2,3] 输出: [3] 示例 2: 输入: [1,1,1,3,3,2,2,2] 输出: [1,2] class Solution { public List<Integer> majorityElement(int[] nums) { List<Integer> res = new Ar…
求众数II 给定一个大小为 n 的数组,找出其中所有出现超过 ⌊ n/3 ⌋ 次的元素. 说明: 要求算法的时间复杂度为 O(n),空间复杂度为 O(1). 示例 1: 输入: [3,2,3] 输出: [3] 示例 2: 输入: [1,1,1,3,3,2,2,2] 输出: [1,2] 摩尔投票法的基本思想很简单,在每一轮投票过程中,从数组中找出一对不同的元素,将其从数组中删除.这样不断的删除直到无法再进行投票,如果数组为空,则没有任何元素出现的次数超过该数组长度的一半.如果只存在一种元素,那么这…
Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. Hint: How many majority elements could it possibly have? Do you have a better hint? Suggest it! 这道题让我们…
Majority Element II Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. Note: The algorithm should run in linear time and in O(1) space. Example 1: Input: [3,2,3] Output: [3] Example 2: Input: [1,1,1,3,3,2,2,2] Ou…
Majority Element II Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. Hint: How many majority elements could it possibly have? Do you have a better hint…
Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 这一题可以用排序之后查看序列正中间那个元素的方法来解.但…
Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. class Solution { public: //O(n) Space compexity vector<int> majorityElement01(vector<int>&…
Total Accepted: 23103 Total Submissions: 91679 Difficulty: Medium Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. Hint: How many majority elements cou…
Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. Hint: How many majority elements could it possibly have? Do you have a better hint? Suggest it! [题目分析]…
Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. Note: The algorithm should run in linear time and in O(1) space. Example 1: Input: [3,2,3] Output: [3] Example 2: Input: [1,1,1,3,3,2,2,2] Output: [1,2] 169. Maj…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 hashmap统计次数 摩尔投票法 Moore Voting 相似题目 参考资料 日期 题目地址:https://leetcode.com/problems/majority-element-ii/description/ 题目描述 Given an integer array of size n, find all elements that ap…
题目描述 给定一个大小为 n 的数组,找出其中所有出现超过 ⌊ n/3 ⌋ 次的元素. 说明: 要求算法的时间复杂度为 O(n),空间复杂度为 O(1). 示例 1: 输入: [3,2,3] 输出: [3] 示例 2: 输入: [1,1,1,3,3,2,2,2] 输出: [1,2] 解题思路 由于数组中出现次数超过 $\frac{1}{3}$ 的数字最多只可能为两个,所以记录两个数字n1.n2,以及他们出现的次数c1.c2,遍历数组并做以下操作: 若当前两数字出现则把对应的次数加1: 若其中一个…
Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 题目标签:Array 题目给了我们一个 nums array, 让我们找出所有 数量超过 n/3 的众数.这一题与 众数之一 的区别在于,众数之一 只要找到一个 众数大于 n/2 的就可以.这一题要找到所…
Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. Note: The algorithm should run in linear time and in O(1) space. Example 1: Input: [3,2,3] Output: [3] Example 2: Input: [1,1,1,3,3,2,2,2] Output: [1,2] 给定一个大小为 …
这题用到的基本算法是Boyer–Moore majority vote algorithm wiki里有示例代码 1 import java.util.*; 2 public class MajorityVote { 3 public int majorityElement(int[] num) { 4 int n = num.length; 5 int candidate = num[0], counter = 0; 6 for (int i : num) { 7 if (counter ==…
就是简单的应用多数投票算法(Boyer–Moore majority vote algorithm),参见这道题的题解. class Solution { public: vector<int> majorityElement(vector<int>& nums) { ,cnt2=,ans1=,ans2=; for(auto n:nums){ if(n==ans1){ cnt1++; } else if(n==ans2){ cnt2++; } ){ ans1=n; cnt1…
Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 解题思路: <编程之美>寻找发帖水王的原题,两次遍历,一次遍历查找可能出现次数超过nums.length/3的数字,(出现三次不同的数即抛弃),第二次验证即可. JAVA实现如下: public Lis…
Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 代码如下:(方法一:超内存) public class Solution { public List<Integer> majorityElement(int[] nums) { List<Int…
Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 解法:参考编程之美129页,寻找发帖水王 代码如下: public class Solution { public List<Integer> majorityElement(int[] nums) {…
题目链接:https://leetcode-cn.com/problems/majority-element-ii/ 题目大意: 略. 分析: k个一起删, 最后check一下即可. 代码如下: #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i) #define PB push_back #define ft first #define sd second class Solution {…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 思路 hashmap统计次数 摩尔投票法 Moore Voting 位运算统计位数 相似题目 参考资料 日期 题目地址:https://leetcode.com/problems/majority-element/ Total Accepted: 110538 Total Submissions: 268289 Difficulty: Easy 题目…
[抄题]: Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. [暴力解法]: 时间分析: 空间分析: [奇…
Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Example 1: Input: [3,2,3] Ou…
Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. Note: The algorithm should run in linear time and in O(1) space. Example 1: Input: [3,2,3] Output: [3] Example 2: Input: [1,1,1,3,3,2,2,2] Output: [1,2] 这道题让我们求出…
寻找多数元素这一问题主要运用了:Majority Vote Alogrithm(最大投票算法)1.Majority Element 1)description Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty…