Given a integer N. Find number of possible ways to represent N as a sum of at most five cubes. Input First line contains N. 1<=N<=125000. Output Output the result Example Input: 64 Output: 2 这种题目..直接暴力吧 #include<cstdio> #include<iostream>…

原文地址:http://blog.csdn.net/ausboyue/article/details/52775281 Linux SSH命令错误:ECDSA host key "ip地址" for  has changed and you have requested strict checking.记录下方便记忆. 解决方案:在终端上输入以下命令: ssh-keygen -R "你的远程服务器ip地址" 目的是清除你当前机器里关于你的远程服务器的缓存和公钥信息,…

2588: Spoj 10628. Count on a tree Time Limit: 12 Sec  Memory Limit: 128 MBSubmit: 5217  Solved: 1233[Submit][Status][Discuss] Description 给定一棵N个节点的树,每个点有一个权值,对于M个询问(u,v,k),你需要回答u xor lastans和v这两个节点间第K小的点权.其中lastans是上一个询问的答案,初始为0,即第一个询问的u是明文. Input 第一…

catalogue . OSSEC . HashSentry: Host-Based IDS in Python . Afick . 检测流程 1. OSSEC OSSEC is an Open Source Host-based Intrusion Detection System. It performs . log analysis . integrity checking . Windows registry monitoring . rootkit detection . real-t…

题目 Source http://www.spoj.com/problems/DQUERY/en/ Description Given a sequence of n numbers a1, a2, ..., an and a number of d-queries. A d-query is a pair (i, j) (1 ≤ i ≤ j ≤ n). For each d-query (i, j), you have to return the number of distinct elem…

Marching Cubes算法是三维离散数据场中提取等值面的经典算法,其主要应用于医学领域的可视化场景,例如CT扫描和MRI扫描的3D重建等. 算法主要的思想是在三维离散数据场中通过线性插值来逼近等值面,具体如下:三维离散数据场中每个栅格单元作为一个体素,体素的每个顶点都存在对应的标量值.如果体素顶点上的值大于或等于等值面值,则定义该顶点位于等值面之外,标记为“0”:而如果体素顶点上的值小于等值面值,则定义该顶点位于等值面之内,标记为“1”.由于每个体素单元有8个顶点,那么共存在2^8 = 2…

SPOJ - GSS3 Can you answer these queries III Description You are given a sequence A of N (N <= 50000) integers between -10000 and 10000. On this sequence you have to apply M (M <= 50000) operations: modify the i-th element in the sequence or for giv…

题目 Source http://codeforces.com/contest/525/problem/E Description Anya loves to fold and stick. Today she decided to do just that. Anya has n cubes lying in a line and numbered from 1 to n from left to right, with natural numbers written on them. She…

这题是学主席树的时候就想写的,,, 但是当时没写(懒) 现在来填坑 = =日常调半天lca(考虑以后背板) 主席树还是蛮好写的,但是代码出现重复,不太好,导致调试的时候心里没底(虽然事实证明主席树部分没出问题) #include <cstdio> #include <algorithm> using namespace std; ]; ]; ,N=,lastans=; ],nex[],list[]; ],h[],fir[],root[],f[],pos[]; ],near[],rm…

在某些数据访问层框架中,会使用show full tables from test like 'demo',来检查数据库的状态.当数据库中表的数量较少时,并没有出现严重的问题.但是当数据库中的表数量多余千个时,且并发数较高时,通过show processlist就会发现show full tables语句绝大部分处于checking permissions状态 | 2 | test | 192.168.15.128:57656 | NULL | Query | 0 | checking perm…