贪心做过去,先对每个时间的左边点进行排序,然后乱搞,当然线段树也可以做 /* ID: jusonal1 PROG: milk2 LANG: C++ */ #include <iostream> #include <fstream> #include <string> #include <cstdio> #include <algorithm> #include <map> #include <cstring> using…

题目 题目描述 有3个农夫每天早上五点钟便起床去挤牛奶,现在第一个农夫挤牛奶的时刻为300(五点钟之后的第300个分钟开始),1000的时候结束.第二个农夫从700开始,1200结束.最后一个农夫从1500开始,2100结束.现在我们可以算出,在一段时间内至少有一个农夫在持续挤牛奶的最长时间间隔为900分钟(1200-300),在他们挤牛奶的过程中,没有人挤牛奶的最长时间间隔为300分钟(1500-1200). 现在有N个农夫,给出他们每个人挤牛奶的开始时刻与结束时刻.分别计算出在一段时间内至少…

挺有趣的一道题,呵呵,不算难 /* ID: jusonal1 PROG: transform LANG: C++ */ #include <iostream> #include <fstream> #include <string> #include <cstdio> #include <algorithm> #include <map> #include <cstring> using namespace std; co…

[BZOJ 1652][USACO 06FEB]Treats for the Cows Description FJ has purchased N (1 <= N <= 2000) yummy treats for the cows who get money for giving vast amounts of milk. FJ sells one treat per day and wants to maximize the money he receives over a given…

NC24017 [USACO 2016 Jan S]Angry Cows 题目 题目描述 Bessie the cow has designed what she thinks will be the next big hit video game: "Angry Cows". The premise, which she believes is completely original, is that the player shoots cows with a slingshot i…

裸的凸包..很好写,废话不说,直接贴代码. ----------------------------------------------------------------------------- #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #include<cmath> #define rep(i,r) for(int i=0;i<r…

/* ID: vincent63 LANG: C TASK: milk2 */ #include <stdio.h> #include<stdlib.h> #include<string.h> struct time{ int begin; int end; int len; }; void sort(struct time t[],int n){ int i,j; struct time temp; ;i<n;i++){ for(j=i;j<n;j++){…

usaco ch1.4 sort(d , d + c, [](int a, int b) -> bool { return a > b; }); 生成与过滤 generator&&filter dfs:简化多重循环,枚举点对与判环 洛谷OJ P1209 [USACO1.3]修理牛棚 Barn Repair P1444 [USACO1.3]虫洞wormhole P3650 [USACO1.3]滑雪课程设计Ski Course Design P2693 [USACO1.3]号码锁…

典型的找欧拉路径的题.先贴下USACO上找欧拉路径的法子: Pick a starting node and recurse on that node. At each step: If the node has no neighbors, then append the node to the circuit and return If the node has a neighbor, then make a list of the neighbors and process them (wh…

二分图的最大匹配.我是用最大流求解.加个源点s和汇点t:s和每只cow.每个stall和t 连一条容量为1有向边,每只cow和stall(that the cow is willing to produce milk in )也连一条容量为1的边.然后就用ISAP. #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #include<vector>…