/* * 240.Search in a 2D Matrix II * 2016-6-17by Mingyang * From left-bottom to right-top * 他这道题目虽说是用了BS,但是并不一定要有mid,这里就从最左下角到右上角 * 这个数大于同一列的,小于同一行的,只要跟target比较以后,就可以要么删除一列,要么删除一行--------找拐点 * 这个题目自己做的时候给出了一个nlog的方案,先是row从下往上走,在同一row里面再继续bs * 但是这个题目的好…

74. Search a 2D Matrix 整个二维数组是有序排列的,可以把这个想象成一个有序的一维数组,然后用二分找中间值就好了. 这个时候需要将全部的长度转换为相应的坐标,/col获得x坐标,%col获得y坐标 class Solution { public: bool searchMatrix(vector<vector<int>>& matrix, int target) { int row = matrix.size(); ) return false; ].s…

Leetcode之二分法专题-240. 搜索二维矩阵 II(Search a 2D Matrix II) 编写一个高效的算法来搜索 m x n 矩阵 matrix 中的一个目标值 target.该矩阵具有以下特性: 每行的元素从左到右升序排列. 每列的元素从上到下升序排列. 示例: 现有矩阵 matrix 如下: [ [1, 4, 7, 11, 15], [2, 5, 8, 12, 19], [3, 6, 9, 16, 22], [10, 13, 14, 17, 24], [18, 21, 23…

240. 搜索二维矩阵 II 240. Search a 2D Matrix II 题目描述 编写一个高效的算法来搜索 m x n 矩阵 matrix 中的一个目标值 target.该矩阵具有以下特性: 每行的元素从左到右升序排列. 每列的元素从上到下升序排列. 每日一算法2019/6/9Day 37LeetCode240. Search a 2D Matrix II 示例: 现有矩阵 matrix 如下: [   [1, 4, 7, 11, 15],   [2, 5, 8, 12, 19],…

Search a 2D Matrix II Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascendin…

Search a 2D Matrix II Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascendin…

Write an efficient algorithm that searches for a value in an m x n matrix, return the occurrence of it. This matrix has the following properties: Integers in each row are sorted from left to right. Integers in each column are sorted from up to bottom…

Search a 2D Matrix II Write an efficient algorithm that searches for a value in an m x n matrix, return the occurrence of it. This matrix has the following properties: Integers in each row are sorted from left to right. Integers in each column are so…

Question: Search a 2D Matrix Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted from left to right. The first integer of each row is greater than the la…

/* * 74.Search in a 2D Matrix * 12.5 by Mingyang * 这里面的对应挺巧的: * 这个就是将2D矩阵转化成1行数组的对应表.所以对于二分查找法的初始值为: * low=0,high=rows*columns-1(总共数值的个数,因为从0开始所以减1). * 为了能够方便在given 2D matrix找到需要比对的值 * 我们还是需要确定行数和列数,通过上表可以看出,行数是position/columns,而列数是position%columns,…