方法一: package testSimple; import java.util.ArrayList; import java.util.Collections; import java.util.Comparator; import java.util.List; public class testCollectionSort { public static void main(String[] args) { List<TblPowerGroup> list = new ArrayLis…
1.java提供的默认list排序方法 主要代码: List<String> list = new ArrayList();list.add("刘媛媛"); list.add("王硕");list.add("李明");list.add("刘迪");list.add("刘布"); //升序Collections.sort(list,Collator.getInstance(java.util.Lo…
1.java提供的默认list排序方法 主要代码: List<String> list = new ArrayList();list.add("刘媛媛"); list.add("王硕"); list.add("李明"); list.add("刘迪"); list.add("刘布"); //升序 Collections.sort(list,Collator.getInstance(java.uti…
sort()是Collections中的静态方法,用于对List容器中的元素排序. 如容器list中存储的是Integer对象 List<Integer> list =Arrays.asList(3, 2, 7, 5, 9, 6); System.out.println(Arrays.toString(list.toArray())); 输出结果为:[3, 2, 7, 5, 9, 6] 使用Collections.sort()对list排序 Collections.sort(list); Sy…
1.排序测试类 package com.ljq.test; import java.util.ArrayList; import java.util.Collections; import java.util.Comparator; import java.util.List; public class UserSort { public static void main(String[] args) { List<User> userList =new ArrayList<User&g…
class User { String name; String age;  public User(String name,String age){  this.name=name;  this.age=age; } public String getAge() {  return age; } public void setAge(String age) {  this.age = age; } public String getName() {  return name; } public…
public static void main(String[] args) { int[] dd = {12,34,46,123,23,2,35,13,543231,65,5645,57}; Arrays.sort(dd); System.out.println(Arrays.toString(dd)); // 常用数组排序,算法是快速排序算法 List<Student> ls = new ArrayList<Student>(); ls.add(new Student(2, &…
首先:定义bean 然后:定义比较器 最后:测试使用 一.userBean package com.butterfly.Class; public class user { private String name; private String sex; private int age; private String birthday; public user(String name,String sex,int age,String birthday){ this.name = name; t…
public static void main(String[] args) throws ParseException { // sort降序排列 List<Date> dates = new ArrayList<>(); SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); Date dd = sdf.parse("2000-11-11 12:12:21")…
List<MenuVo> child_menus = new ArrayList<MenuVo>(); for (MenuVo menuVo : child_menus) { System.out.println("menuBVo=======" + menuVo.getSortId()); } Collections.sort(child_menus, new Comparator<MenuVo>() { public int compare(Me…