Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses. Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of heaters so that all…

Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses. Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of heaters so that all…

Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses. Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of heaters so that all…

这是悦乐书的第239次更新,第252篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第106题(顺位题号是475).冬天来了!您在比赛期间的第一份工作是设计一个固定温暖半径的标准加热器,以加热所有房屋.现在,您可以在水平线上获得房屋和加热器的位置,找出加热器的最小半径,以便所有房屋都能被这些加热器覆盖.因此,您的输入将分别是房屋和加热器的位置,您的预期输出将是加热器的最小半径.例如: 输入:[1,2,3],[2] 输出:1 说明:唯一的加热器在位置2,如果我们使用半径…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 遍历 日期 题目地址:https://leetcode.com/problems/heaters/ 题目描述 Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the…

problem 475. Heaters solution1: class Solution { public: int findRadius(vector<int>& houses, vector<int>& heaters){ , cur = , j = ; sort(houses.begin(), houses.end()); sort(heaters.begin(), heaters.end()); ; i<houses.size(); i++) {…

Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses. Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of heaters so that all…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

https://leetcode.com/problems/heaters/ 开始的时候,下面的代码对于两边数字完全一样的情况,测试不通过.原因是heater会有重复情况,这时候对于飘红部分就不会往前面继续检查.所以把<改成<=让相同的情况也继续往前面走,走到最后一个,就可以了.Accepted! package com.company; import java.util.Arrays; class Solution { public int findRadius(int[] houses,…