Source: PAT A1037 Magic Coupon (25 分) Description: The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product…

1037. Magic Coupon (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you m…

1037 Magic Coupon (25 分) The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the sh…

1037 Magic Coupon(25 分) The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the sho…

1037 Magic Coupon (25 分)   The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the…

The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the shop also offers some bonus…

https://pintia.cn/problem-sets/994805342720868352/problems/994805451374313472 The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times…

The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the shop also offers some bonus…

The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the shop also offers some bonus…

题目 The magic shop in Mars is ofering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the shop also ofers some bonu…

The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the shop also offers some bonus…

The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the shop also offers some bonus…

一.技术总结 这也是一个贪心算法问题,主要在于想清楚,怎么解决输出和最大,两个数组得确保符号相同位相乘,并且绝对值尽可能大. 可以用两个vector容器存储,然后排序从小到大或是从大到小都可以,一次从两端开始相乘,保证符号相同. 二.参考代码 #include<iostream> #include<algorithm> #include<vector> using namespace std; bool cmp(int a, int b){ return a >…

#include<iostream> #include<vector> #include<stdio.h> #include<algorithm> using namespace std; int cmp(int a,int b) { return a<b; } int main() { int n,i,j,tem; while(scanf("%d",&n)!=EOF) { getchar(); vector<int&…

题目说了那么多,就是给你两个序列,分别选取元素进行一对一相乘,求得到的最大乘积. 将两个序列的正和负数分开,排个序,然后分别将正1和正2前面的相乘,负1和负2前面的相乘,累加和即可. #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cmath> #include <vector> using namespa…

浙大计算机研究生保研复试上机考试-2011年  贪心: 注意:输入输出用scanf  printf 可以加快速度,用cin WA #include<iostream> #include<cstring> #include<cstdio> #include<string> #include<cmath> #include<algorithm> using namespace std; #define MAX 1000000 __int6…

#include <iostream> #include <algorithm> #include <vector> using namespace std; int nc,np; vector<int> vc,vp; int tmp; int i,j; int total; int main(){ cin>>nc; for(i=0;i<nc;i++){ cin>>tmp; vc.push_back(tmp); } cin>…

#include <cstdio> #include <cstdlib> #include <vector> #include <algorithm> using namespace std; void print(vector<int> &v) { int len = v.size(); ; i<len; i++) { printf(" %d", v[i]); } printf("\n");…

简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<vector> using namespace std; +; int n,m; long long a[maxn]; long long b[m…

题意: 输入一个正整数N(<=1e5),接下来输入N个整数.再输入一个正整数M(<=1e5),接下来输入M个整数.每次可以从两组数中各取一个,求最大的两个数的乘积的和. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ],b[]; ],d[]; int cnta,cntb,cntc,cntd; int main(){ int n,m; cin&g…

1037. Magic Coupon (25) 时间限制 100 ms 内存限制 32000 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you m…

准备每天刷两题PAT真题.(一句话题解) 1001 A+B Format  模拟输出,注意格式 #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; string ans = ""; int main() { ; cin >> a >> b; c = a + b; ) {…

博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6102219.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 时隔两年,又开始刷题啦,这篇用于PAT甲级题解,会随着不断刷题持续更新中,至于更新速度呢,嘿嘿,无法估计,不知道什么时候刷完这100多道题. 带*的是我认为比较不错的题目,其它的难点也顶多是细节处理的问题~ 做着做着,发现有些题目真的是太水了,都不想写题解了…

树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 1053 Path of Equal Weight   1064 Complete Binary Search Tree 完全二叉树的顺序存储,BST的性质 1066 Root of AVL Tree 构建AVL树,模板题,需理解记忆 1079 Total Sales of Supply Chain…

早期部分代码用 Java 实现.由于 PAT 虽然支持各种语言,但只有 C/C++标程来限定时间,许多题目用 Java 读入数据就已经超时,后来转投 C/C++.浏览全部代码:请戳 本文谨代表个人思路,欢迎讨论;) 1031. Hello World for U (20) 题意 将给定的字符串打印出 U 型. 比如给定helloworld,打印出 1 2 3 4 5 h d e l l r lowo 设定左边的字符个数为 n1,底边字符个数为 n2,右边字符个数为 n3.需要满足 n1 = n3…

最短路径 Emergency (25)-PAT甲级真题(Dijkstra算法) Public Bike Management (30)-PAT甲级真题(Dijkstra + DFS) Travel Plan (30)-PAT甲级真题(Dijkstra + DFS,输出路径,边权) All Roads Lead to Rome (30)-PAT甲级真题-Dijkstra + DFS Online Map (30)-PAT甲级真题(Dijkstra + DFS) 最短路径扩展问题 要求数最短路径有多…

专题一  字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d",&a,&b); sum=a+b; ) { printf ("-"); sum=-sum; } ; ) { s[top++]=; } ) { s[top++]=sum%; sum/=; } ;i>=;i--) { printf ("%d"…

D. Magic Numbers time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Consider the decimal presentation of an integer. Let's call a number d-magic if digit d appears in decimal presentation of…

A magic index in an array A[0...n-1] is defined to be an index such that A[i] = i. Given a sorted array of distinct integers, write a method to find a magic index, if one exists, in array A. FOLLOW UP What if the values are not distinct? public int g…

介绍 在Python中,所有以"__"双下划线包起来的方法,都统称为"Magic Method",例如类的初始化方法 __init__ ,Python中所有的魔术方法均在官方文档中有相应描述,但是对于官方的描述比较混乱而且组织比较松散.很难找到有一个例子. 构造和初始化 每个Pythoner都知道一个最基本的魔术方法, __init__ .通过此方法我们可以定义一个对象的初始操作.然而,当调用 x = SomeClass() 的时候, __init__ 并不是第一个…