978. Basic Calculator https://www.lintcode.com/problem/basic-calculator/description public class Solution { /** * @param s: the given expression * @return: the result of expression */ public int calculate(String s) { // Write your code here Stack<Int…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the given expression is…

Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. You may assume that the given ex…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . The expression string contains only non-nega…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . The expression string contains only non-nega…

Given an expression such as expression = "e + 8 - a + 5" and an evaluation map such as {"e": 1}(given in terms of evalvars = ["e"] and evalints = [1]), return a list of tokens representing the simplified expression, such as […

实现一个基本的计算器来计算一个简单的字符串表达式. 字符串表达式仅包含非负整数,+, - ,*,/四种运算符和空格 . 整数除法仅保留整数部分. 你可以假定所给定的表达式总是有效的. 一些例子: "3+2*2" = 7" 3/2 " = 1" 3+5 / 2 " = 5注意: 不要使用eval 内置的函数库. 详见:https://leetcode.com/problems/basic-calculator-ii/description/ Jav…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the given expression is…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the given expression is…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . Example 1: Input: "1 + 1" Output: 2 Exa…

Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, /operators and empty spaces . The integer division should truncate toward zero. Example 1: Input: "3+2*2" Ou…

227. 基本计算器 II 227. Basic Calculator II 题目描述 实现一个基本的计算器来计算一个简单的字符串表达式的值. 字符串表达式仅包含非负整数,+,-,*,/ 四种运算符和空格.整数除法仅保留整数部分. LeetCode227. Basic Calculator II中等 示例 1: 输入: "3+2*2" 输出: 7 示例 2: 输入: " 3/2 " 输出: 1 示例 3: 输入: " 3+5 / 2 " 输出:…

Basic Calculator I Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the g…

［抄题］: Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. Example 1: Input: "3+2*2&q…

2018-09-27 22:02:36 一.Basic Calculator II 问题描述: 问题求解: sign用来保存前一个符号,用num来记录数字,如果碰到一个符号或者到达结尾,则需要进行入栈操作,这个时候需要结合符号进行相应的运算. public int calculate(String s) { if (s == null || s.length() == 0) return 0; int res = 0; Stack<Integer> stack = new Stack<&…

题目 Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. You may assume that the given…

▶ 两个四则表达式运算的题目,第 770 题 Basic Calculator IV 带符号计算不会做 Orz,第 772 题 Basic Calculator III 要收费 Orz. ▶ 自己的全能版代码,28 ms,采用表达式中缀转后缀,然后利用栈来计算.支持加减乘除幂模,一模一样的代码刷掉了这两题,就是效率比较低,28 ms class Solution { public: int calculate(string s)//计算器,输入表达式,输出计算结果 { string out; m…

题目 Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the given expression…

题目:https://leetcode.com/problems/basic-calculator/ Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty sp…

本博客介绍leetcode上的一道不难,但是比较经典的算法题. 题目如下: Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You ma…

Basic Calculator I Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the g…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the given expression is…

Basic Calculator Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the giv…

Basic Calculator II 题目 思路 和这个一样:Basic Calculator I 代码 class ExpressionTransformation { public: string trans_to_postfix_expression_to_s(string); // 将得到的表达式转化为后缀表达式 long long int calculate_from_postfix_expression(); // 依据后缀表达式计算值 private: vector<string…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 栈 参考资料 日期 题目地址:https://leetcode.com/problems/basic-calculator/description/ 题目描述 Implement a basic calculator to evaluate a simple expression string. The expression string may c…

[LeetCode]227. Basic Calculator II 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/basic-calculator-ii/description/ 题目描述: Implement a basic calculator to evaluate a simple exp…

Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. You may assume that the given ex…

Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. You may assume that the given ex…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the given expression is…

原题链接在这里:https://leetcode.com/problems/basic-calculator/ Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and emp…