UVa 1025 A Spy in the Metro （DP动态规划）

【UVa 1025 A Spy in the Metro （DP动态规划）】的更多相关文章

UVA - 1025 A Spy in the Metro[DP DAG]

UVA - 1025 A Spy in the Metro Secret agent Maria was sent to Algorithms City to carry out an especially dangerous mission. After several thrilling events we find her in the first station of Algorithms City Metro, examining the time table. The Algorit…

UVA 1025 -- A Spy in the Metro (DP)

UVA 1025 -- A Spy in the Metro 题意: 一个间谍要从第一个车站到第n个车站去会见另一个,在是期间有n个车站,有来回的车站,让你在时间T内时到达n,并且等车时间最短,输出最短等车时间. 思路: 先用一个has_train[t][i][0]来表示在t时刻,在车站i,是否有往右开的车.同理,has_train[t][i][1]用来保存是否有往左开的车. 用d(i,j)表示时刻i,你在车站j,最少还需要等待多长时间.边界条件是d(T,n)=0,其他d(T,i)为正无…

UVa 1025 A Spy in the Metro（动态规划）

传送门 Description Secret agent Maria was sent to Algorithms City to carry out an especially dangerous mission. After several thrilling events we find her in the first station of Algorithms City Metro, examining the time table. The Algorithms City Metro…

World Finals 2003 UVA - 1025 A Spy in the Metro（动态规划）

分析:时间是一个天然的序,这个题目中应该决策的只有时间和车站,使用dp[i][j]表示到达i时间,j车站在地上已经等待的最小时间,决策方式有三种,第一种:等待一秒钟转移到dp[i+1][j]的状态,代价为1.第二种:如果可以则向右上车,转移到dp[i+t][j+1],无代价,t为列车行驶时间.第三种与第二种相同.初始状态为dp[0][1] = 0,其他为INF.答案为dp[T][n]. 代码如下: #include<iostream> #include<cstdio> #inclu…

uva 1025 A Spy in the Metro 解题报告

A Spy in the Metro Time Limit: 3000MS 64bit IO Format: %lld & %llu Submit Status uDebug Secret agent Maria was sent to Algorithms City to carry out an especially dangerous mission. After several thrilling events we find her in the first station o…

UVA 1025 A Spy in the Metro 【DAG上DP/逆推/三维标记数组+二维状态数组】

Secret agent Maria was sent to Algorithms City to carry out an especially dangerous mission. After several thrilling events we find her in the first station of Algorithms City Metro, examining the time table. The Algorithms City Metro consists of a s…