LeetCode & Q268-Missing Number-Easy】的更多相关文章

题目描述: Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in linear runtime complexity. Could you implement…
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in linear runtime complexity. Could you implement it usi…
转载:http://www.cnblogs.com/grandyang/p/4756677.html Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in li…
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. Example 1 Input: [3,0,1] Output: 2 Example 2 Input: [9,6,4,2,3,5,7,0,1] Output: 8 Note:Your algorithm should run in linear runtime c…
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example, Given nums = [0, 1, 3] return 2. Note: Your algorithm should run in linear runtime complexity. Could you implement it u…
1.题目大意 Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0]. Not…
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in linear runtime complexity. Could you implement it usi…
题意:先将0, 1, 2, ..., n放入数组,然后去掉其中一个值,找到那个值. 这题与singe number 是一个类型,变形的地方就是首先需要将0, 1, 2, ..., n再次放入这个数组,这样就和singe number 一样. class Solution { public: int missingNumber(std::vector<int>& nums) { ; ; i < nums.size(); ++i){ ans ^= nums[i]; } ; i <…
只要存在一种因数分解后,其因子是2,3,5中的一种或多种,就算是ugly数字. 思路: 以2/3/5作为除数除后,最后结果等于1的就是ugly数字 Runtime: 4 ms, faster than 98.64% of C++ online submissions for Ugly Number. class Solution { public: bool isUgly(int num) { == && num > ) num /= ; == && num >…
题目: Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. Example 1: Input: [3,0,1] Output: 2 Example 2: Input: [9,6,4,2,3,5,7,0,1] Output: 8 Note:Your algorithm should run in linear run…