【LeetCode 31 Next Permutation（下一个全排列）】的更多相关文章

[LeetCode] 31. Next Permutation 下一个排列

Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order). The replaceme…

leetCode 31.Next Permutation (下一个字典序排序) 解题思路和方法

Next Permutation  Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending ord…

[leetcode]31. Next Permutation下一个排列

Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order). The replaceme…

31. Next Permutation (下一个全排列)

Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order). The replaceme…

LeetCode 31 Next Permutation（下一个全排列）

题目链接: https://leetcode.com/problems/next-permutation/?tab=Description   Problem :寻找给定int数组的下一个全排列(要求:be in-place)   倒序查找到该数组中第一个满足后面的数字大于前面的数字的下标i (当前下标 i 指向 后面的那个比较大的数)     参考代码:  package leetcode_50; /*** * * @author pengfei_zheng * 下一个全排列 */ publi…

[array] leetcode - 31. Next Permutation - Medium

leetcode - 31. Next Permutation - Medium descrition Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such arrangement is not possible, it must rearrange it as the lowest possible…

LeetCode 31 Next Permutation / 60 Permutation Sequence [Permutation]

LeetCode 31 Next Permutation / 60 Permutation Sequence [Permutation] <c++> LeetCode 31 Next Permutation 给出一个序列,求其下一个排列 STL中有std::next_permutation这个方法可以直接拿来用 也可以写一个实现程序: 从右往左遍历序列,找到第一个nums[i-1]<num[i]的位置,记p = i-1. 如果第一步没有找到,说明整个序列满足单调递减,也就是最大的排列,那…

NextPermutation，寻找下一个全排列

问题描述:给定一个数组是一个全排列,寻找下一个全排列.例如123->132, 321->123, 115->151. 算法分析:从后往前寻找顺序,找到后从往前寻找第一个大于当前元素,即第一个逆序,然后元素交换,重新sort当前元素后面的元素.如果都是逆序,reverse数组. package Leecode_Permutation; import java.util.Arrays; public class NextPermutation { public void nextPermut…

leetcode 31. Next Permutation(字典序的下一个)

描述: Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order). The repla…

LeetCode 31. Next Permutation （下一个排列）

Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order). The replaceme…