Given a binary tree, return the inorder, preorder, postorder traversal of its nodes' values. Example: Input: [1,null,2,3] 1 \ 2 / 3 inorder Output: [1,3,2] preorder Output: [1,2,3] postorder Output: [3,2,1] 这三个题目的思路及总结都在LeetCode questions conlusion_I…

Construct Binary Tree from Preorder and Inorder Traversal Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. 可与Construct Binary Tree from Inorder and Postorder Trav…

Problem Link: https://oj.leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/ The basic idea is same to that for Construct Binary Tree from Inorder and Postorder Traversal. We solve it using a recursive function. First, we…

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作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 日期 题目地址:https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/description/ 题目描述 Given preorder and inorder traversal of a tree, construct t…

Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. 通过树的中序序列和前序序列来构建一棵树. 例如:一棵树的前序序列是1-2-3,中序序列有5种可能,分别是1-2-3.2-1-3.1-3-2.2-3-1.3-2-1.不同的中序序列对应着不同的树的结构,这几棵树分别是[1,nul…

Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree.从前序以及中序的结果中构造二叉树,这里保证了不会有两个相同的数字,用递归构造就比较方便了: class Solution { public: TreeNode* buildTree(vector<int>& preor…

给定一个二叉树,以集合方式返回其中序/先序方式遍历的所有元素. 有两种方法,一种是经典的中序/先序方式的经典递归方式,另一种可以结合栈来实现非递归 Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. OJ's Binary Tree Serialization: The s…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/construct-binary-tree-from-preorder-and-postorder-traversal/description/ 题目描述 Return any binary tree that matches the given preorder and p…

构造方式跟中序与后序全然一样,并且一般都习惯正着来,所以更简单. 代码是之前写的,没实用库函数,不应该. TreeNode *buildIt(vector<int> &preorder, int start1, vector<int> &inorder, int start2, int len){ if(len <= 0) return NULL; TreeNode *root = new TreeNode(preorder[start1]); int i =…