Scores 求五维偏序(≤).强制在线. \(n,q\le 50000\) 烂大街的题解 考虑如果我们能用bitset找到每一维有哪些比询问点小,然后把每一维的结果取交集,得到的就是答案了. 然后对每一维分块处理前缀,询问时二分得到排名,将前面整块的和末尾的合并一下就行了. 时间复杂度\(O(\frac{nq}{32})\).分块对时间复杂度几乎没什么影响,重要的是bitset的操作. #include<bits/stdc++.h> #define co const #define il i…

题意:50000个5维向量,50000次询问每一维都不大于某一向量的向量个数,强制在线. 思路:做完这题才知道bitset效率这么高,自己本地测试了下1s可以操作1010个bit,orz简单粗暴 令S(i)表示第i维比当前向量的i维小的向量集,则答案为count(∩S(i)),0≤i‹5 每个向量都可以和一个id绑定(取下标就行了),绑定后就可以考虑bitset了.分别按每一维排序,每隔√N个位置预处理下当前位置之前的id的bitset 查询时,对每一维二分得到最大位置,然后用1个预处理的结果+…

北京网络赛的题- -.当时没思路,听大神们说是分块+bitset,想了一下发现确实可做,就试了一下,T了好多次终于过了 题意: 初始有n个人,每个人有五种能力值,现在有q个查询,每次查询给五个数代表查询的五种能力值,输出有多少个人每种能力值都比查询的小 n和q都是50000,每种能力值最大也为50000 思路: 对于某一个大小的能力值,有哪些人的此项能力值比他小可以用一个50000的bitset表示.这样我们在查询的时候就可以拿到5个对应的bitset,对其进行and就可以得出最终的人数 这样每…

题意:给你50000个五维点(a1,a2,a3,a4,a5),50000个询问(q1,q2,q3,q4,q5),问已知点里有多少个点(x1,x2,x3,x4,x5)满足(xi<=qi,i=1,2,3,4,5),强制在线. 一看题的一个直接思路是五维树状数组,算了一下复杂度还不如暴力判,遂不会做.赛后问了一下大神们,知道是分块+bitset,觉得处理挺巧妙的,就留一份题解在这里. 具体的做法是这样子的.定义一个bitset<maxn> bs[i][k],表示第i维前k块所对应的点的bits…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

D. Memory and Scores   Memory and his friend Lexa are competing to get higher score in one popular computer game. Memory starts with score a and Lexa starts with score b. In a single turn, both Memory and Lexa get some integer in the range [ - k;k] (…

function script_faster_rcnn_demo() close all; clc; clear mex; clear is_valid_handle; % to clear init_key run(fullfile(fileparts(fileparts(mfilename('fullpath'))), 'startup')); %% -------------------- CONFIG -------------------- opts.caffe_version = '…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

做到这题时卡了不少时间,参考了别人的解法,觉得挺不错的,还挺巧妙. SELECT s2.Score,s1.Rank From ( SELECT S1.Score, COUNT(*) as Rank FROM (SELECT DISTINCT Score from Scores) as S1, (SELECT DISTINCT Score from Scores) as S2 Where S1.Score<=S2.Score Group By S1.Score ) s1 ,Scores s2 WH…

Using names.txt (right click and 'Save Link/Target As...'), a 46K text file containing over five-thousand first names, begin by sorting it into alphabetical order. Then working out the alphabetical value for each name, multiply this value by its alph…

Memory and Scores 题目链接:http://codeforces.com/contest/712/problem/D dp 因为每轮Memory和Lexa能取的都在[-k,k],也就是说每轮两人分数的变化量在[-2k,2k]: 故可以定义状态:dp[times][diff]为第times次Memory和Lexa的分数差为diff的方案数. 而dp[times][diff]可以从dp[times-1][diff-2k]到dp[times-1][diff+2k]转移而来: 又因为变化…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

Score 很好得到: select Score from Scores order by Score desc; 要得到rank, 可以通过比较比当前Score 大的Score 的个数得到: select Score, (select count(distinct Score) from Scores where Score>=s.Score) Rank where Scores s order by Score desc; 或者: select s.Score ,count(distinct…

Kyle is a student of Programming Monkey Elementary School. Just as others, he is deeply concerned with his grades. Last month, the school held an examination including five subjects, without any doubt, Kyle got a perfect score in every single subject…

D. Memory and Scores 题目连接: http://codeforces.com/contest/712/problem/D Description Memory and his friend Lexa are competing to get higher score in one popular computer game. Memory starts with score a and Lexa starts with score b. In a single turn, b…

机器学习的评估 PR曲线用于positive类数据占比比较小,或者你更加在意false postion(相比于false negative):其他情况采用ROC曲线:比如Demo中手写体5的判断,因为只有少量5,所以从ROC上面来看分类效果不错,但是从PR曲线可以看到分类器效果不佳.   y_scores = sgd_clf.decision_function([some_digit]) decision_function代表的是参数实例到各个类所代表的超平面的距离:在梯度下滑里面特有的(随机森…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

题目链接    https://leetcode.com/problems/rank-scores/description/ 题意:对所有的分数按照降序进行排序,查询出分数和排名,排名相同的输出相同名次 此种解法在leetcode中未通过,看错误提示,好像是数据的精确度问题,不知道为什么. 附上一个通过的(mysql):https://blog.csdn.net/travel_1/article/details/51589706 思路: 1.首先查出 不重复的所有分数排名 select dist…

问题描述 解决方案 select sc.Score, (select count(*) from (select distinct Score from Scores ) ds where ds.Score>= sc.Score ) Rank from Scores sc order by Score desc…

# -*- coding: utf-8 -*- """ Created on Wed Aug 10 08:10:35 2016 @author: Administrator """ ''' 关于:cross_validation.scores 此处cross_validation.scores并不是cross_validation的scores, 而是分类函数(本文是clf,svm)的scores分成K部分K-1是训练1次是测试共K个scores…

#1236 : Scores 时间限制:4000ms 单点时限:4000ms 内存限制:256MB 描述 Kyle is a student of Programming Monkey Elementary School. Just as others, he is deeply concerned with his grades. Last month, the school held an examination including five subjects, without any do…

2015北京网络赛 J Scores 题意:50000组5维数据,50000个询问,问有多少组每一维都不大于询问的数据 思路:赛时没有思路,后来看解题报告也因为智商太低看了半天看不懂.bitset之前没用过,查了下发现其实就是一个二进制表示,这里的每一位就表示原序中的状态.  建一个bitset<50000> bs[6][sqrt(50000)], bs[i][j] 就表示在第i维上前j个块中的数据在原序中是哪些位置. #include <iostream> #include &l…

time limit per test2 seconds memory limit per test512 megabytes inputstandard input outputstandard output Memory and his friend Lexa are competing to get higher score in one popular computer game. Memory starts with score a and Lexa starts with score…

I believe that there are two types of people who get high scores in English exams: 1) have high intelligence. 2) spend time several times more than others on English learning so that their English levels outperform the level that the English exam req…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" be…

import java.util.*; public class ArraySortScore { //完成 main 方法 public static void main(String[] args) { int counter=0; int[] scores=new int[]{89 , -23 , 64 , 91 , 119 , 52 , 73}; SortScore(scores); int index=0; while(index<scores.length) { System.out…

[Codeforces712D] Memory and Scores(DP+前缀和优化)(不用单调队列) 题面 两个人玩游戏,共进行t轮,每人每轮从[-k,k]中选出一个数字,将其加到自己的总分中.已知两人的初始得分分别为a和b,求第一个人最后获胜的方案数.两种方案被认为是不同的,当且仅当存在其中一轮,其中一人选到的数字不同.a, b, t≤100,k≤1000 分析 两个人的操作是独立的,设\(dp1[i][j]\)表示第1个人玩i轮得到j分的方案数,第2个人同理 则有\(dp1[0][a]=…