[LeetCode] 72. Edit Distance 编辑距离】的更多相关文章

Given two words word1 and word2, find the minimum number of operations required to convert word1 to word2. You have the following 3 operations permitted on a word: Insert a character Delete a character Replace a character Example 1: Input: word1 = "h…
Edit Distance Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.) You have the following 3 operations permitted on a word: a) Insert a character b) Delete a char…
传送门 Description Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.) You have the following 3 operations permitted on a word: a) Insert a characterb) Delete a cha…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 记忆化搜索 动态规划 日期 题目地址:https://leetcode.com/problems/edit-distance/description/ 题目描述 Given two words word1 and word2, find the minimum number of operations required to convert w…
最小编辑距离,动态规划经典题. Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.) You have the following 3 operations permitted on a word: a) Insert a characterb) Delete a cha…
Given two words word1 and word2, find the minimum number of operations required to convert word1 to word2. You have the following 3 operations permitted on a word: Insert a character Delete a character Replace a character 题意: 给定两个串串: word1, word2;  找…
Given two words word1 and word2, find the minimum number of operations required to convert word1 to word2. You have the following 3 operations permitted on a word: Insert a character Delete a character Replace a character Example 1: Input: word1 = "h…
Leetcode72 看起来比较棘手的一道题(列DP方程还是要大胆猜想..) DP方程该怎么列呢? dp[i][j]表示字符串a[0....i-1]转化为b[0....j-1]的最少距离 转移方程分三种情况考虑 分别对应三中操作 因为只需要三个值就可以更新dp[i][j] 我们可以把空间复杂度降低到O(n) Replace word1[i - 1] by word2[j - 1] (dp[i][j] = dp[i - 1][j - 1] + 1 (for replacement)); Delet…
原题 dp 利用二维数组dp[i][j]存储状态: 从字符串A的0~i位子字符串 到 字符串B的0~j位子字符串,最少需要几步.(每一次删增改都算1步) 所以可得边界状态dp[i][0]=i,dp[0][j]=j. 以及状态转移方程 即当比较 word1[i] 和 word2[j] 字符 相等 时,所需步数与 word1[i-1] 和 word2[j-1] 相等. 状态转移方程为:dp[i][j]=dp[i-1][j-1] 否则,状态转移方程为dp[i][j]= min(dp[i-1][j-1]…
72. Edit Distance Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.) You have the following 3 operations permitted on a word: a) Insert a character b) Delete a…