Virtual Friends These days, you can do all sorts of things online. For example, you can use various websites to make virtual friends. For some people, growing their social network (their friends, their friends’ friends, their friends’ friends’ friend…

Virtual Friends Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3677    Accepted Submission(s): 1059 Problem Description These days, you can do all sorts of things online. For example, you can u…

题意 给出 N 对 数字 然后 每次从一对中 取出一个数字 判断 能否有一种取出的方案 取出的每个数字 都是不同的 思路 将每一对数字 连上一条边 然后 最后 判断每一个连通块里面 边的个数 是否 大于等于 点的个数 用并查集判断 AC代码 #include <cstdio> #include <cstring> #include <ctype.h> #include <cstdlib> #include <cmath> #include <…

You are the boss of ACM (Association for Control over Minds), an upstanding company with a single goal of world domination. Yesterday, you woke up, and saw that the weather was clear, and the birds were singing. “Another day, another world domination…

These days, you can do all sorts of things online. For example, you can use various websites to make virtual friends. For some people, growing their social network (their friends, their friends' friends, their friends' friends' friends, and so on), h…

Virtual Friends Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11092    Accepted Submission(s): 3221 Problem Description These days, you can do all sorts of things online. For example, you can…

These days, you can do all sorts of things online. For example, you can use various websites to make virtual friends. For some people, growing their social network (their friends, their friends' friends, their friends' friends' friends, and so on), h…

题目比较简单,但作为长久不写题之后的热身题还是不错的. 统计每组朋友的朋友圈的大小. 如果a和b是朋友,这个朋友圈的大小为2,如果b和c也是朋友,那么a和c也是朋友,此时这个朋友圈的大小为3. 输入t,表示接下来有t组数据. 每组数据有n组朋友关系. 接下来n行,每行一组朋友关系,然后输出这组朋友的朋友圈大小,即有多少朋友. 然后又是t组数据……(这点好坑)重复上述输入,直到数据结束. 因为最多有10^5个人,那么如果用线性字符串数组保存人名,肯定超时得不要不要的,所以要用map(每次操作时间复…

题意:人与人交友构成关系网,两个人交友,相当于两个朋友圈的合并,问每个出两人,他们目前所在的关系网中的人数. 分析:用并查集,其实就是求每个集合当前的人数.对于人名的处理用到了字典树. 注意:1.题目给出的n是指n对关系,上限有2*n个人.  2.题目很没有意思的既说了有多组数据,又要求输入组数.实际上还是多组数据. #include<cstdio> #include<cstring> #include<algorithm> using namespace std; ;…

转自:http://blog.csdn.net/shahdza/article/details/7779230 [HDU]1213 How Many Tables 基础并查集★1272 小希的迷宫 基础并查集★1325&&poj1308 Is It A Tree? 基础并查集★1856 More is better 基础并查集★1102 Constructing Roads 基础最小生成树★1232 畅通工程 基础并查集★2120 Ice_cream's world I 基础并查集★212…