UVA323 Jury Compromise 题解 考虑用动态规划.该问题要求解的最终状态为,选出的 \(m\) 个人,使得辩方总分与控方总分差的绝对值最小,总分之和最大.即 \(\left| D(\mathcal{J}) - P(\mathcal{J}) \right|\) 最小,同时 \(D(\mathcal{J}) + P(\mathcal{J})\)最大. 使用三维 \(dp\) 数组记录状态,\(dp[i][j][k]\) 表示前 \(i\) 个人选出 \(j\) 个人同时辩方总分和为…

思路:背包类DP 提交:3次 错因:没有注意得分的上下界导致 RE 显示 WA 题解: 我们很容易的想到把两种分数做一个差,来尽量背到 \(0\) . 那最大化总分呢?这时我们可以用两种分数的和作为物品的价值. 记录方案呢?每个状态开一个 vector ,来记录转移的物品.(今天新学)(虽然空间大但是方便写) 代码: #include<cstdio> #include<iostream> #include<algorithm> #include<cstring&g…

Jury Compromise Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 33737   Accepted: 9109   Special Judge Description In Frobnia, a far-away country, the verdicts in court trials are determined by a jury consisting of members of the general…

题目链接: http://poj.org/problem?id=1015 Jury Compromise Time Limit: 1000MSMemory Limit: 65536K 问题描述 In Frobnia, a far-away country, the verdicts in court trials are determined by a jury consisting of members of the general public. Every time a trial is…

Jury Compromise Time Limit: 1000MS   Memory Limit: 65536K Total Submissions:32355   Accepted:8722   Special Judge Description In Frobnia, a far-away country, the verdicts in court trials are determined by a jury consisting of members of the general p…

作为一个oier,以及大学acm党背包是必不可少的一部分.好久没做背包类动规了.久违地练习下-.- dd__engi的背包九讲:http://love-oriented.com/pack/ 鸣谢http://blog.csdn.net/eagle_or_snail/article/details/50987044,这里有大部分比较有趣的dp练手题. hud 2602 01背包板子题 #include<cstdio> #include<iostream> #include<cs…

[题解]Jury Compromise(链表+DP) 传送门 题目大意 给你\(n\le 200\)个元素,一个元素有两个特征值,\(c_i\)和\(d_i\),\(c,d \in [0,20]\),现在请你选出\(m\le 20\)个元素使得\(\sum c+\sum d\)最大,使得$|\sum c - \sum d|最小,输出\sum c \(和\)\sum d$和一组合法方案. 分析 是DP无误了. 我们可以先不考虑绝对值,平移一下值域,假如说我们知道\(\sum c +- \sum d…

\(Jury Compromise\) \(solution:\) 这道题很有意思,它的状态设得很...奇怪.但是它的数据范围实在是太暴露了.虽然当时还是想了好久好久,出题人设了几个限制(首先要两个的总和差值最小)(然后需要让它的总和最大).我们发现每一个人的顺序是无关紧要的,这其实又提示了我们可以背包.但我们发现很难设状态,我们需要让我们的总差值接近0,但是我们在加人的时候我们的总差值可能会增大也可能会减小,这不符合背包的基本要求,所以我们不能将总差值设为我们背包的权值.于是一个奇妙的想法产生…

K - Jury Compromise 参考:ACM POJ 1015 Jury Compromise(陪审团的人选,动态规划题,难) 说实话真有点难想,用一个DP[i][j]来表示在选取i个人,辩控差为j(j值已做些许处理)时辩控总分的最大值,用三个for循环来更新这个值.具体思路还是看参考博客吧.... 优先队列默认top()是最大值,如果写成priority_queue<int,vector<int>,greater<int> > top()则为最小值 代码: /…

题目: In Frobnia, a far-away country, the verdicts in court trials are determined by a jury consisting of members of the general public. Every time a trial is set to begin, a jury has to be selected, which is done as follows. First, several people are…