problem 697. Degree of an Array 题意:首先是原数组的度,其次是和原数组具有相同的度的最短子数组.那么最短子数组就相当于子数组的首末数字都是统计度的数字. solution1: class Solution { public: int findShortestSubArray(vector<int>& nums) { ; unordered_map<int, int> m; unordered_map<int, pair<int,…

[LeetCode]697. Degree of an Array 解题报告 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/degree-of-an-array/description/ 题目描述: Given a non-empty array of non-negative integers nums, the degree of this array is defined as the maximum frequency of…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 求出最短相同子数组度的长度 使用堆求最大次数和最小长度 保存最左边出现位置和最右边出现位置 日期 题目地址:https://leetcode.com/problems/degree-of-an-array/description/ 题目描述 Given a non-empty array of non-negative integers nums,…

[26]Remove Duplicates from Sorted Array Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant mem…

697. Degree of an Array - LeetCode Question 697. Degree of an Array - LeetCode Solution 理解两个概念: 数组的度:[1,2,2,3,1]这个数组,去重后的元素为[1,2,3],每个元素在原数组中重复的次数分别是221,数组的度就是元素最大重复次数,这个数组中元素最大重复次数就是2 连续子数组:和字符串中的了串概念类似,数组元素顺序保持不变,取其中一部分,该题就是求在度相同的情况下最小连续子数组的长度 思路:数…

[题目] Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no d…

[Description] Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target,…

题目: Given a non-empty array of non-negative integers nums, the degree of this array is defined as the maximum frequency of any one of its elements. Your task is to find the smallest possible length of a (contiguous) subarray of nums, that has the sam…

Given a non-empty array of non-negative integers nums, the degree of this array is defined as the maximum frequency of any one of its elements. Your task is to find the smallest possible length of a (contiguous) subarray of nums, that has the same de…

Given a non-empty array of non-negative integers nums, the degree of this array is defined as the maximum frequency of any one of its elements. Your task is to find the smallest possible length of a (contiguous) subarray of nums, that has the same de…

［抄题］: Given a non-empty array of non-negative integers nums, the degree of this array is defined as the maximum frequency of any one of its elements. Your task is to find the smallest possible length of a (contiguous) subarray of nums, that has the s…

Given a non-empty array of non-negative integers nums, the degree of this array is defined as the maximum frequency of any one of its elements. Your task is to find the smallest possible length of a (contiguous) subarray of nums, that has the same de…

Given a non-empty array of non-negative integers nums, the degree of this array is defined as the maximum frequency of any one of its elements. Your task is to find the smallest possible length of a (contiguous) subarray of nums, that has the same de…

problem 977. Squares of a Sorted Array solution: class Solution { public: vector<int> sortedSquares(vector<int>& A) { for(auto &a:A) a *=a; sort(A.begin(), A.end()); return A; } }; 参考1. Leetcode_easy_977. Squares of a Sorted Array; 完…

problem 961. N-Repeated Element in Size 2N Array solution: class Solution { public: int repeatedNTimes(vector<int>& A) { unordered_map<int, int> amap; for(auto a:A) { amap[a]++; } , max_val; for(auto a:amap) { if(a.second>max_num) { max…

problem 941. Valid Mountain Array solution: class Solution { public: bool validMountainArray(vector<int>& A) { ) return false; ], max_id = ; ; i<A.size(); ++i) { if(A[i]>max) { max = A[i]; max_id = i; } } || max_id==A.size()-) return false…

problem 896. Monotonic Array solution1: class Solution { public: bool isMonotonic(vector<int>& A) { int inc = true, dec = true; ; i<A.size(); ++i) { inc &= (A[i]>=A[i-]); dec &= (A[i]<=A[i-]); } return inc || dec; } }; solution2…

problem 905. Sort Array By Parity solution1: class Solution { public: vector<int> sortArrayByParity(vector<int>& A) { vector<int> even, odd; for(auto a:A) { ==) even.push_back(a); else odd.push_back(a); } even.insert(even.end(), odd.…

problem 922. Sort Array By Parity II solution1: class Solution { public: vector<int> sortArrayByParityII(vector<int>& A) { int n = A.size(); , j=; i<n, j<n; ) { ==) i += ; ==) j += ; if(j<n) swap(A[i], A[j]); } return A; } }; 参考 1…

problem 852. Peak Index in a Mountain Array solution1: class Solution { public: int peakIndexInMountainArray(vector<int>& A) { return max_element(A.begin(), A.end())-A.begin(); } }; solution2: class Solution { public: int peakIndexInMountainArra…

problem 1122. Relative Sort Array 参考 1. Leetcode_easy_1122. Relative Sort Array; 2. helloacm; 完…

problem 665. Non-decreasing Array 题意:是否能够将数组转换为非减数组. solution: 难点在于理解如何对需要修改的元素进行赋值: class Solution { public: bool checkPossibility(vector<int>& nums) { , n = nums.size(); ; i<n; i++) { ]) { ) return false; || nums[i-] <= nums[i]) nums[i-]…

problem 532. K-diff Pairs in an Array 题意:统计有重复无序数组中差值为K的数对个数. solution1: 使用映射关系: 统计数组中每个数字的个数.我们可以建立每个数字和其出现次数之间的映射,然后遍历哈希表中的数字,如果k为0且该数字出现的次数大于1,则结果res自增1:如果k不为0,且用当前数字加上k后得到的新数字也在数组中存在,则结果res自增1. class Solution { public: int findPairs(vector<int>&…

一.排序 1.sort -- 从最低到最高排序,删除原有的键名,赋予新的键名[字母比数字高] 2.rsort -- 逆向排序(最高到最低),删除原有的键名,赋予新的键名[字母比数字高] 3.asort -- 正向排序,保持索引关系  4.arsort --逆向排序,保持索引关系     5.ksort --按照键名排序    6.krsort --按照键名逆向排序 (1)纯英文:$fruits = array("d" => "lemon", "a&q…

Remove Duplicates from Sorted Array II Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array A = [1,1,1,2,2,3], Your function should return length = 5, and A is now [1,1,2,2,3].     用两个指针,…

Search in Rotated Sorted Array II Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array.   与I类似,只是在二…

Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise retu…

Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplic…

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 我的思路: 太混乱了 不提了.注意关键区分依据 排好序的一定是从小到大的 看大神的吧: b…

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array A = […