POJ 3279 Fliptile(翻格子) Time Limit: 2000MS    Memory Limit: 65536K Description - 题目描述 Farmer John knows that an intellectually satisfied cow is a happy cow who will give more milk. He has arranged a brainy activity for cows in which they manipulate an…

1647: [Usaco2007 Open]Fliptile 翻格子游戏 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 423  Solved: 173[Submit][Status][Discuss] Description Farmer John knows that an intellectually satisfied cow is a happy cow who will give more milk. He has arranged a…

[Usaco2007 Open]Fliptile 翻格子游戏 题目 Farmer John knows that an intellectually satisfied cow is a happy cow who will give more milk. He has arranged a brainy activity for cows in which they manipulate an M x N grid (1 <= M <= 15; 1 <= N <= 15) of…

问题 B: [Usaco2007 Open]Fliptile 翻格子游戏 时间限制: 5 Sec  内存限制: 128 MB 题目描述 Farmer John knows that an intellectually satisfied cow is a happy cow who will give more milk. He has arranged a brainy activity for cows in which they manipulate an M x N grid (1 <=…

1647: [Usaco2007 Open]Fliptile 翻格子游戏 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 702  Solved: 281[Submit][Status][Discuss] Description Farmer John knows that an intellectually satisfied cow is a happy cow who will give more milk. He has arranged a…

POJ.3279 Fliptile (搜索+二进制枚举+开关问题) 题意分析 题意大概就是给出一个map,由01组成,每次可以选取按其中某一个位置,按此位置之后,此位置及其直接相连(上下左右)的位置(如果有)的0变成1,1变成0.现在求需要按多少次,才能使得整个map全部变成0. 此题解法与 UVA.11464 Even Parity 有异曲同工之妙. 首先可以看出,最多每个位置按一次,因为再按的话,相当于没按.如果我们枚举每一个位置是否按的话,2^(n*n)的复杂度爆炸. 接着思考,其实相对来…

题目传送门 /* 题意:问最少翻转几次使得棋子都变白,输出翻转的位置 状态压缩+枚举:和之前UVA_11464差不多,枚举第一行,可以从上一行的状态知道当前是否必须翻转 */ #include <cstdio> #include <cstring> #include <algorithm> using namespace std; ; const int INF = 0x3f3f3f3f; int a[MAXN][MAXN]; int b[MAXN][MAXN]; in…

问题 B: [Usaco2007 Open]Fliptile 翻格子游戏 时间限制: 5 Sec  内存限制: 128 MB 题目描述 Farmer John knows that an intellectually satisfied cow is a happy cow who will give more milk. He has arranged a brainy activity for cows in which they manipulate an M x N grid (1 <=…

以防万一,题目原文和链接均附在文末.那么先是题目分析: [一句话题意] 给定长宽的黑白棋棋盘摆满棋子,每次操作可以反转一个位置和其上下左右共五个位置的棋子的颜色,求要使用最少翻转次数将所有棋子反转为黑色所需翻转的是哪些棋子(这句话好长...). [题目分析] 盯着奇怪的题目看了半天发现和奶牛没什么卵关系..奶牛智商高了产奶高是什么鬼说法... 这题刚开始被放到搜索的分类下了..然而这和搜索有什么关系..没经验所以想了各种和搜索沾边的方法,结果没想出解法,直到看了网上的题解,压根不是搜索啊有木有.…

[题目链接]click here~~ [题目大意]: 农夫约翰知道聪明的牛产奶多. 于是为了提高牛的智商他准备了例如以下游戏. 有一个M×N 的格子,每一个格子能够翻转正反面,它们一面是黑色,还有一面是白色.黑色的格子翻转后就是白色.白色的格子翻转过来则是黑色. 游戏要做的就是把全部的格子都翻转成白色. 只是由于牛蹄非常大,所以每次翻转一个格子时.与它上下左右相邻接的格子也会被翻转.由于翻格子太麻烦了.所以牛都想通过尽可能少的次数把全部格子都翻成白色.如今给定了每一个格子的颜色.请求出用最小步数…