You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad ve…

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad ve…

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad ve…

题意:找到第一个出问题的版本 二分查找,注意 mid = l + (r - l + 1) / 2;因为整数会溢出 // Forward declaration of isBadVersion API. bool isBadVersion(int version); class Solution { public: int firstBadVersion(int n) { , r = n , ans ; while(l <= r){ ) / ; if(!isBadVersion(mid)){ l…

题目描述: You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a…

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad ve…

题目: You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a ba…

704. Binary Search 1.使用start+1 < end,这样保证最后剩两个数 2.mid = start + (end - start)/2,这样避免接近max-int导致的溢出 3.start.end直接等于mid 4.最后比较两个位置 class Solution { public: int search(vector<int>& nums, int target) { if(nums.empty()) ; ; ; int mid; < end){ m…

problem 278. First Bad Version solution1:遍历: // Forward declaration of isBadVersion API. bool isBadVersion(int version); class Solution { public: int firstBadVersion(int n) { ; while(ver<n) { if(isBadVersion(ver)) return ver; ver++; } return ver; } }…

Question 278. First Bad Version Solution 题目大意:产品有5个版本1,2,3,4,5其中下一个版本依赖上一个版本,即版本4是坏的,5也就是坏的,现在要求哪个版本是第一个坏的. 思路:二分法,middle-1好,middle坏,middle就是第一个坏的版本 Java实现: /* The isBadVersion API is defined in the parent class VersionControl. boolean isBadVersion(i…