#-*- coding: UTF-8 -*- # Definition for singly-linked list.# class ListNode(object):#     def __init__(self, x):#         self.val = x#         self.next = Noneclass Solution(object):    def removeElements(self, head, val):        """      …

Remove Linked List Elements Remove all elements from a linked list of integers that have value val. ExampleGiven: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6Return: 1 --> 2 --> 3 --> 4 --> 5 Credits:Special thanks to @mith…

Remove Linked List Elements Remove all elements from a linked list of integers that have value *val*. Example: Input: 1->2->6->3->4->5->6, val = 6 Output: 1->2->3->4->5 解 /** * Definition for singly-linked list. * struct List…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 双指针 递归 日期 题目地址:https://leetcode.com/problems/remove-linked-list-elements/description/ 题目描述 Remove all elements from a linked list of integers that have value val. Example Given…

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#-*- coding: UTF-8 -*-class Solution(object):    def isPalindrome(self, head):        """        :type head: ListNode        :rtype: bool        """        if head==None or head.next==None:return True        resList=[]       …

#-*- coding: UTF-8 -*-#双指针思想,两个指针相隔n-1,每次两个指针向后一步,当后面一个指针没有后继了,前面一个指针的后继就是要删除的节点# Definition for singly-linked list.# class ListNode(object):#     def __init__(self, x):#         self.val = x#         self.next = Noneclass Solution(object):    def re…

#-*- coding: UTF-8 -*- # Definition for singly-linked list.# class ListNode(object):#     def __init__(self, x):#         self.val = x#         self.next = Noneclass Solution(object):    def deleteDuplicates(self, head):        if head==None or head.…

#-*- coding: UTF-8 -*- class Solution(object):    def removeElement(self, nums, val):        """        :type nums: List[int]        :type val: int        :rtype: int        """        for i in range(len(nums)-1,-1,-1):      …

#-*- coding: UTF-8 -*-class Solution(object):    def removeDuplicates(self, nums):        """        :type nums: List[int]        :rtype: int        """        if len(nums)<=1:return len(nums)        pre=0;next=1        wh…