1030 Travel Plan (30 分)   A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her starting…

https://pintia.cn/problem-sets/994805342720868352/problems/994805464397627392 A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler t…

https://www.patest.cn/contests/pat-a-practise/1030 找最短路,如果有多条找最小消耗的,相当于找两次最短路,可以直接dfs,数据小不会超时. #include<cstdio> #include<string> #include<cstring> #include<vector> #include<iostream> #include<queue> #include<bitset&g…

A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her starting city and the destination.…

题目 A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her starting city and the destinatio…

1030 Travel Plan (30)(30 分) A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her startin…

1030 Travel Plan (30 分) A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her starting ci…

1030. Travel Plan (30) A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her starting cit…

题意: 输入N,M,S,D(N,M<=500,0<S,D<N),接下来M行输入一条边的起点,终点,通过时间和通过花费.求花费最小的最短路,输入这条路径包含起点终点,通过时间和通过花费. trick: 找了半小时bug终于发现是给dis数组赋初值时范围是1~N,这道题点是从0~N-1的,故初次只通过了第0组数据,初始化改一下边界即可AC. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h>…

先处理出最短路上的边.变成一个DAG,然后在DAG上进行DFS. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<queue> #include<vector> using namespace std; const int INF=0x7FFFFFFF; ; int n,m,…