题目链接 Problem Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk> is a subsequence of X if there exists a…

链接:http://acm.hdu.edu.cn/showproblem.php?pid=1159 题解 #include<iostream> #include<cstring> using namespace std; ],B[]; //存放字符串 ][]; //存放到字符串a第 i+1个字符,字符串b第 j+1个字符为止的最大长度公共子序列的长度 int main(){ while(~scanf("%s%s",A,B)){ int alen=strlen(A…

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 24489    Accepted Submission(s): 10823 Problem Description A subsequence of a given sequence is the given sequence with some e…

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 18765    Accepted Submission(s): 7946 Problem Description A subsequence of a given sequence is the given sequence with some ele…

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 37725    Accepted Submission(s): 17301 Problem Description A subsequence of a given sequence is the given sequence with some el…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1159 Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 37551    Accepted Submission(s): 17206 Problem Description A subsequence of…

传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1159 Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 47676    Accepted Submission(s): 21890 Problem Description A subsequence of…

Problem Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk> is a subsequence of X if there exists a stri…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1159 Problem Description 给定序列的子序列是给定的序列,其中有一些元素(可能没有)被遗漏. 给定一个序列X = <x1,x2,...,xm>如果存在严格递增的序列<i1,i2,...,则另一个序列Z = <z1,z2,...,zk>是X的子序列. ...,ik>的索引,使得对于所有j = 1,2,...,k,xij = zj. 例如,Z = <a,…

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 55301    Accepted Submission(s): 25537 Problem Description A subsequence of a given sequence is the given sequence with some el…

A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk> is a subsequence of X if there exists a strictly increasing sequ…

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 39559    Accepted Submission(s): 18178 Problem Description A subsequence of a given sequence is the given sequence with some el…

问题 L: Common Subsequence 时间限制: 1 Sec  内存限制: 32 MB 提交: 70  解决: 40 [提交][状态][讨论版] 题目描述 A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <…

题意: 两个字符串,判断最长公共子序列的长度. 思路: 直接看代码,,注意边界处理 代码: char s1[505], s2[505]; int dp[505][505]; int main(){ while(scanf("%s%s",s1,s2)!=EOF){ int l1=strlen(s1); int l2=strlen(s2); mem(dp,0); dp[0][0]=((s1[0]==s2[0])?1:0); rep(i,1,l1-1) if(s1[i]==s2[0]) dp…

HDU 1159 题目大意:给定两个字符串,求他们的最长公共子序列的长度 解题思路:设字符串 a = "a0,a1,a2,a3...am-1"(长度为m), b = "b0, b1, b2, b3 ... bn-1"(长度为n), 它们的最长公共子序列为c = "c0, c1, c2, ... ck-1",长度为k, dp[i][j]定义为子串 "a0,a1,...,ai-1" 和 子串"b0,b1,...,bj-1…

HDU 1159 Common Subsequence 最长公共子序列 题意 给你两个字符串,求出这两个字符串的最长公共子序列,这里的子序列不一定是连续的,只要满足前后关系就可以. 解题思路 这个当然要使用动态规划了. 这里\(dp[i][j]\)代表第一个串的前\(i\)个字符和第二个串的前\(j\)个字符中最长的公共子序列的最长长度,递推关系如下: \[ d[i][j]= \begin{cases} dp[i-1][j-1]+1 & \text{if} &str1[i]==str2[j…

HDOJ 1159 Common Subsequence[DP] Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 44280 Accepted Submission(s): 20431 Problem Description A subsequence of a given sequence is the given sequence wit…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1159 Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 25416    Accepted Submission(s): 11276 Problem Description A subsequence of…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1159 Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 18201    Accepted Submission(s): 7697 Problem Description A subsequence of…

2017-08-06 15:41:04 writer:pprp 刚开始学dp,集训的讲的很难,但是还是得自己看,从简单到难,慢慢来(如果哪里有错误欢迎各位大佬指正) 题意如下: 给两个字符串,找到其中大的公共子序列,每个样例输出一个数: 最长公共子串(Longest Common Substirng)和最长公共子序列(Longest Common Subsequence,LCS)的区别为: 子串是串的一个连续的部分,子序列则是从不改变序列的顺序,而从序列中去掉任意的元素而获得新的序列: 也就是说…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1159 题意: 求最长公共子序列. 题解: (LCS模板题) 表示状态: dp[i][j] = max len of LCS a串匹配到第i位,b串匹配到第j位,此时的最长公共子序列长度. 如何转移: 首先,一个明显的决策是,如果a[i] == b[j],那么此一定要匹配.(贪心) 所以分两种情况: (1)a[i] == b[j]:dp[i][j] = dp[i-1][j-1] + 1 (2)a[i]…

Problem Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, -, xm> another sequence Z = <z1, z2, -, zk> is a subsequence of X if there exists a strictly…

题意:给定两个字符串,让你找出它们之间最长公共子序列(LCS)的长度. 析:很明显是个DP,就是LCS,一点都没变.设两个序列分别为,A1,A2,...和B1,B2..,d(i, j)表示两个字符串LCS长度. 当A[i] = B[j] 时,这个最长度就是上一个长度加1,即:d(i, j) = d(i-1, j-1) + 1; 当A[i] != B[j] 时,那就是前面的最长长度(因为即使后面的不成立,也不会影响前面的),即:d(i, j) = max{d(i-1, j), d(i, j-1)}…

链接: http://acm.hdu.edu.cn/showproblem.php?pid=1159 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28195#problem/A Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 17621…

http://acm.hdu.edu.cn/showproblem.php?pid=5791 Two Problem Description   Alice gets two sequences A and B. A easy problem comes. How many pair of sequence A' and sequence B' are same. For example, {1,2} and {1,2} are same. {1,2,4} and {1,4,2} are not…

问题 说明该问题在生物学中的实际意义 Biological applications often need to compare the DNA of two (or more) different organisms. A strand of DNA consists of a string of molecules called bases, where the possible bases are adenine, guanine, cytosine, and thymine(腺嘌呤,鸟嘌…

Problem Description 小A想通过合理投资银行理财产品达到收益最大化.已知小A在未来一段时间中的收入情况,描述为两个长度为n的整数数组dates和earnings,表示在第dates[i]天小A收入earnings[i]元(0<=i<n).银行推出的理财产品均为周期和收益确定的,可描述为长度为m的三个整数数组start.finish和interest_rates, 若购买理财产品i(0<=i<m),需要在第start[i]天投入本金,在第finish[i]天可取回本…

Common Subsequence Time Limit: 2 Seconds      Memory Limit: 65536 KB A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk…

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 18387    Accepted Submission(s): 7769 Problem Description A subsequence of a given sequence is the given sequence with some el…

Common Subsequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 34819 Accepted Submission(s): 15901 Problem Description A subsequence of a given sequence is the given sequence with some element…