SGU 181.X-Sequence】的更多相关文章

E - X-Sequence Time Limit:500MS     Memory Limit:4096KB     64bit IO Format:%I64d & %I64u Submit Status Practice SGU 181 Description Let {xi} be the infinite sequence of integers:  1) x0 = A;  2) xi = (alpha * xi-1^2 + beta * xi-1 + gamma) mod M, for…
时间限制:0.5s 空间限制:4M 题意: 令X0=A, Xi=(a*Xi-1^2,b*Xi-1+c)%m; 求Xk,(0<=k<=109),(0<=a,b<=100),(1<m<1000); Solution:                 题目的关键在于m的范围,1000的范围显然是会在取余后出现循环的.                 只要得出循环的数列的长度以及它的每一个数,和任意一个循环的起点位置.就可以算出Xk 值.                 要注意…
SGU 106 题意:问你有多少个<x,y>,满足ax+by+c=0,x1<=x<=x2,y1<=y<=y2 收货:拓展欧几里得求解的是这种方程,ax+by=1,gcd(a,b)=1 如果gcd(a,b)不等于1的话,那么你直接传进egcd函数里求出的x,y还是a1x+b1y=1的解,a1=a/gcd(a,b),b1=b/gcd(a,b) 还有注意y1,x0,y0会和系统的里面变量冲突 #include<bits/stdc++.h> #define de(x…
题目链接:http://acm.sgu.ru/problem.php?contest=0&problem=455 Due to the slow 'mod' and 'div' operations with int64 type, all Delphi solutions for the problem 455 (Sequence analysis) run much slower than the same code written in C++ or Java. We do not gua…
链接: http://vj.acmclub.cn/contest/view.action?cid=168#problem/E 时限:250MS     内存:4096KB     64位IO格式:%I64d & %I64u 提交 状态 练习 SGU 105 问题描述 There is sequence 1, 12, 123, 1234, ..., 12345678910, ... . Given first N elements of that sequence. You must determ…
http://acm.sgu.ru/problemset.php?contest=0&volume=1 101 Domino 欧拉路 102 Coprime 枚举/数学方法 103 Traffic Lights 最短路 104 Little Shop of Flowers 动态规划 105 Div 3 找规律 106 The Equation 扩展欧几里德 107 987654321 Problem 找规律 108 Self-numbers II 枚举+筛法递推 109 Magic of Dav…
oracle创建序列化: CREATE SEQUENCE seq_itv_collection            INCREMENT BY 1  -- 每次加几个              START WITH 1399       -- 从1开始计数              NOMAXVALUE        -- 不设置最大值              NOCYCLE               -- 一直累加,不循环              CACHE 10; oracle修改序列…
功能:备份存储过程,视图,函数触发器,Sequence序列号等准备工作:--1.创建文件夹 :'E:/OracleBackUp/ProcBack';--文本存放的路径--2.执行:create or replace directory MyProcBakPath as 'E:/OracleBackUp/ProcBack';--3.赋权限:sqlplus /nologconn user/pswd as sysdbagrant select on DBA_OBJECTS to user;--4.创建…
环境:Oracle 11.2.0.4 DG 故障现象: 客户在备库告警日志中发现GAP sequence提示信息: Mon Nov 21 09:53:29 2016 Media Recovery Waiting for thread 1 sequence 12034 Fetching gap sequence in thread 1, gap sequence 12034-12078 Mon Nov 21 09:55:20 2016 FAL[client]: Failed to request…
The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…