1065. A+B and C (64bit)】的更多相关文章

1065. A+B and C (64bit) (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HOU, Qiming Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the po…
1065 A+B and C (64bit) (20 分)   Given three integers A, B and C in [−], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists o…
1065 A+B and C (64bit) (20 分) Given three integers A, B and C in [−2^​63​​,2​^63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow,…
1065. A+B and C (64bit) (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HOU, Qiming Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the po…
1065. A+B and C (64bit) (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HOU, Qiming Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the po…
1065 A+B and C (64bit)(20 分) Given three integers A, B and C in [−2​63​​,2​63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, eac…
1065 A+B and C (64bit) (20 分)   Given three integers A, B and C in [−], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists o…
1065 A+B and C (64bit) Given three integers A, B and C in [−2​63​​,2​63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each cons…
题目链接 https://www.patest.cn/contests/pat-a-practise/1065 思路 因为 a 和 b 都是 在 long long 范围内的 但是 a + b 可能会溢出 long long 但是 不会溢出 long double 所以 用long double 就能轻松解决了 或者 用大数加法 也行 AC代码 #include <cstdio> #include <cstring> #include <ctype.h> #includ…
Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line co…
#include<stdio.h> #include <math.h> int main() { long long a,b,c,sum; int n,i; while(scanf("%d",&n)!=EOF) { ;i<=n;i++) { getchar(); scanf("%lld%lld%lld",&a,&b,&c); sum = a + b; int ifis; &&b>&a…
题目 Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10).  Then T test cases follow, each consists of a single lin…
因为会溢出,因此判断条件需要转化.变成b>c-a #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<queue> #include<algorithm> using namespace std; long long a,b,c; int main() { int T; scanf("%d",&T);…
Given three integers A, B and C in [-2^63, 2^63], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line…
第一眼以为是大数据,想套个大数据模板,后来发现不需要.因为A.B.C的大小为[-2^63, 2^63],用long long 存储他们的值和sum. 接下来就是分类讨论:如果A > 0, B < 0 或者 A < 0, B > 0,sum不会溢出,直接和C判断比较即可.如果A > 0, B > 0,sum可能会溢出, 溢出的话为负数,所以sum < 0时候说明溢出了,那么肯定是大于C的.如果A < 0, B < 0,sum可能会溢出,同理,sum &g…
Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line co…
代码: import java.util.*; import java.math.*; public class Main { public static void main(String args[]) { Scanner cin=new Scanner(System.in); int t=cin.nextInt(); for(int i=1;i<=t;i++) { BigInteger a,b,c; a=cin.nextBigInteger(); b=cin.nextBigInteger()…
Given three integers A, B and C in [−], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists of a single line containing three…
题意: 输入三个整数A,B,C(long long范围内),输出是否A+B>C. trick: 测试点2包括溢出的数据,判断一下是否溢出即可. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int t; ci…
Given three integers A, B and C in [−], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists of a single line containing three…
cin的话,处理不了这么大的数?? 要拐回scanf("%lld"): 啊啦搜…
甲级1065 1065 A+B and C (64bit) (20 point(s)) Given three integers A, B and C in [−2​63​​,2​63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test ca…
1065. A+B and C (64bit) (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HOU, Qiming Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the po…
1065 A+B and C (64bit)(20 分) Given three integers A, B and C in [−2​63​​,2​63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, eac…
这次的题目来源是 2013 年 10 月 7 日下午的浙大计算机研究生招生机试题. 这次题目的难度,按姥姥的说法是:『比普通的 PAT 要难了 0.5 个点.我是把自己的题目从 1.0 到 5.0 以 0.5 的间距分难度级别的,PAT(A)难度一般在 1.5-4.5 之间,保研考试一般在 2.0-5.0 之间.PAT(B)大概是 1.0-2.5 的难度.』. 个人认为,其中 1066 模拟 AVL 插入的实现有些细节容易弄错,而 1068 只要会简单的 DP,也就没有问题了,1065 和 10…
2019/4/3 1063 Set Similarity n个序列分别先放进集合里去重.在询问的时候,遍历A集合中每个数,判断下该数在B集合中是否存在,统计存在个数(分子),分母就是两个集合大小减去分子. // 1063 Set Similarity #include <set> #include <map> #include <cstdio> #include <iostream> #include <algorithm> using name…
博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6102219.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 时隔两年,又开始刷题啦,这篇用于PAT甲级题解,会随着不断刷题持续更新中,至于更新速度呢,嘿嘿,无法估计,不知道什么时候刷完这100多道题. 带*的是我认为比较不错的题目,其它的难点也顶多是细节处理的问题~ 做着做着,发现有些题目真的是太水了,都不想写题解了…
树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 1053 Path of Equal Weight   1064 Complete Binary Search Tree 完全二叉树的顺序存储,BST的性质 1066 Root of AVL Tree 构建AVL树,模板题,需理解记忆 1079 Total Sales of Supply Chain…
1001 A+B Format (20) 输入:两个数a,b,-1000000 <= a, b <= 1000000 输出:a+b,并以每3个用逗号隔开的形式展示. 思路一: 1)计算出a+b的值,赋给sum.判断sum<0,则先输出一个“”-”号,并将sum=-sum(转换为正值):判断sum==0时,则输出0: 2)然后将sum存到一个数组num[10]中,将sum数值的低位存到数组的低位(个位存在数组第1位),用一个while循环:num[i]=sum%10,sum=sum/10;…
本文为PAT甲级分类汇编系列文章. 计算类,指以数学运算为主或为背景的题. 题号 标题 分数 大意 1058 A+B in Hogwarts 20 特殊进制加法 1059 Prime Factors 25 分解素因数 1060 Are They Equal 25 一定精度下两数是否相等 1065 A+B and C (64bit) 20 大数加法与比较 1069 The Black Hole of Numbers 20 黑洞数 1073 Scientific Notation 20 科学计数法还…