[USACO07NOV]牛栏Cow Hurdles】的更多相关文章

P2888 [USACO07NOV]牛栏Cow Hurdles Floyd $n<=300$?果断Floyd 给出核心式,自行体会 $d[i][j]=min(d[i][j],max(d[i][k],d[k][j]))$ #include<iostream> #include<cstdio> #include<cstring> using namespace std; int max(int a,int b){return a>b?a:b;} int min(…
题目描述 Farmer John wants the cows to prepare for the county jumping competition, so Bessie and the gang are practicing jumping over hurdles. They are getting tired, though, so they want to be able to use as little energy as possible to jump over the hu…
题目戳 题目描述 Farmer John wants the cows to prepare for the county jumping competition, so Bessie and the gang are practicing jumping over hurdles. They are getting tired, though, so they want to be able to use as little energy as possible to jump over th…
题目描述 Farmer John wants the cows to prepare for the county jumping competition, so Bessie and the gang are practicing jumping over hurdles. They are getting tired, though, so they want to be able to use as little energy as possible to jump over the hu…
OJ题号:洛谷2888 思路:修改Floyd,把边权和改为边权最大值.另外注意是有向图. #include<cstdio> #include<algorithm> using namespace std; #define inf 0x7fffffff int main() { int n,m,t; scanf("%d%d%d",&n,&m,&t); ][n+]; ;i<=n;i++) { ;j<=n;j++) { d[i][j…
直接floyd.. ---------------------------------------------------------------------------- #include<cstdio> #include<cstring> #include<algorithm> #include<iostream>   #define rep( i , n ) for( int i = 0 ;  i < n ; ++i ) #define clr(…
1641: [Usaco2007 Nov]Cow Hurdles 奶牛跨栏 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 424  Solved: 272[Submit][Status] Description Farmer John 想让她的奶牛准备郡级跳跃比赛,贝茜和她的伙伴们正在练习跨栏.她们很累,所以她们想消耗最少的能量来跨栏. 显然,对于一头奶牛跳过几个矮栏是很容易的,但是高栏却很难.于是,奶牛们总是关心路径上最高的栏的高度. 奶牛的训练场…
Cow Hurdles Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9337   Accepted: 4058 Description Farmer John wants the cows to prepare for the county jumping competition, so Bessie and the gang are practicing jumping over hurdles. They are…
Description Farmer John wants the cows to prepare for the county jumping competition, so Bessie and the gang are practicing jumping over hurdles. They are getting tired, though, so they want to be able to use as little energy as possible to jump over…
http://poj.org/problem?id=3615 (题目链接) 题意 给出一张有向图,求从u到v最大边最小的路径的最大边.→_→不会说话了.. Solution 好久没写Floyd了,水一发.邻接表都不用打... 代码 // poj3615 #include<algorithm> #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #inclu…