Determine whether an integer is a palindrome. Do this without extra space. class Solution { public: bool isPalindrome(int x) { ) return false; //别忘了负数的情况 ) return true; ; ; int leftDigit, rightDigit, base; while(tmp){ pHead*=; tmp /= ; } ){ leftDigit…

Reverse Integer Reverse digits of an integer. Example1: x =  123, return  321 Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have alr…

/* Determine whether an integer is a palindrome. Do this without extra space. click to show spoilers. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using…

9. Palindrome Number Total Accepted: 136330 Total Submissions: 418995 Difficulty: Easy Determine whether an integer is a palindrome. Do this without extra space. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of conv…

9 - Palindrome Number Determine whether an integer is a palindrome. Do this without extra space. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using extra…

Determine whether an integer is a palindrome. Do this without extra space.(不要使用额外的空间) Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using extra space. You…

Palindrome Number time=434ms 负数不是回文数 public class Solution { public boolean isPalindrome(int x) { int palindrome=0; int revers=x; if(revers<0) return false; else{ while(revers>0){ int m=revers%10; palindrome=m+palindrome*10; revers=revers/10; } if(p…

主题链接:http://acm.hdu.edu.cn/showproblem.php? pid=5062 Problem Description A positive integer x can represent as (a1a2-akak-a2a1)10 or (a1a2-ak−1akak−1-a2a1)10 of a 10-based notational system, we always call x is a Palindrome Number. If it satisfies 0<…

第一个题目是将整数进行反转,这个题实现反转并不难,主要关键点在于如何进行溢出判断.溢出判断再上一篇字符串转整数中已有介绍,本题采用其中的第三种方法,将数字转为字符串,使用字符串比较大小的方法进行比较. 代码如下: class Solution { public: int reverse(int x) { ]={,,,,,,,,,}; ]; ,flag=; ) flag=; else ) { flag=-; x=-x; } else ; ; ) { getnum[count]=(x%); x=x/…

9. Palindrome Number 题目: Determine whether an integer is a palindrome. Do this without extra space. click to show spoilers. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the…