You are given a sequence of n integers a1, a2, ..., an. Determine a real number x such that the weakness of the sequence a1 - x, a2 - x, ..., an - x is as small as possible. The weakness of a sequence is defined as the maximum value of the poorness o…

题意:一个数组arr,一个数字x,要使arr-x的最大子段最小,问该最小值. 三分x,复杂度logn,内层是最大子段的模板,只能用n复杂度的.因为是绝对值最大,正负各求一次,取大的.精度卡得不得了,要1e-12左右才能过.看着数据才调出精度的. 乱码: //#pragma comment(linker,"/STACK:1024000000,1024000000") #include<iostream> #include<cstdio> #include<s…

2017-08-27 17:24:07 writer:pprp 题意简述: • Codeforces 578C Weakness and poorness• 给定一个序列A• 一个区间的poorness定义为这个区间内和的绝对值• weakness等于所有区间最大的poorness• 求一个x使得,序列A全部减x后weakness最小• 1 ≤ n ≤ 2 * 1e5 这里用到了最大连续区间的和的知识点·,可以看上一篇博客 通过三分找最小值 AC代码如下: /* @theme:myprogram…

C. Weakness and Poorness Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/578/problem/C Description You are given a sequence of n integers a1, a2, ..., an. Determine a real number x such that the weakness of the sequence a1 -…

E. Weakness and Poorness time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a sequence of n integers a1, a2, ..., an. Determine a real number x such that the weakness of the seq…

题目描述: E. Weakness and Poorness time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a sequence of n integers a1, a2, ..., *a**n*. Determine a real number x such that the weakness…

C. Weakness and Poorness time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a sequence of n integers a1, a2, ..., an. Determine a real number x such that the weakness of the seq…

[题目]C. Weakness and Poorness [题意]给定含n个整数的序列ai,定义新序列为ai-x,要使新序列的最大子段和绝对值最小,求实数x.n<=2*10^5. [算法]二分||三分||计算几何(凸包) [题解]Editorial 令正数最大子段和为A,负数最大子段和为B,绝对值是max(A,B).当x从小到大变化时,A由大变小,B由小变大. 容易发现这是一个下凸函数,可以用三分法求解. 但是,这道题卡精度(-11会WA,-12会T),解决方法是根据复杂度把循环次数卡到极限而不…

开始算法基础学习的第一天 今天学习的内容是三分搜索 相对来说很基础的内容(还是觉得脑子不够用) 三分搜索主要用于凸函数查找极大值. (盗个图) 如图所示 若要查找该函数的最大值 可以考虑和二分法一样的思路,即用L,R两个端点去不断地逼近这个最大点 但是在这里仅用一个mid中值是不够的 因此添加了一个mmid = (mid+R)/2 判断函数在mid和mmid两点的大小就可以进一步判断极值存在于哪一段中 用一个便于理解的办法,我们分成以下两种情况来讨论: 1.mid,mmid在最大值的同一侧:这时…

Problem Description In the Dark forest, there is a Fairy kingdom where all the spirits will go together and Celebrate the harvest every year. But there is one thing you may not know that they hate walking so much that they would prefer to stay at hom…