7-10 多项式A除以B (25 分)】的更多相关文章

7-10 多项式A除以B (25分)   这仍然是一道关于A/B的题,只不过A和B都换成了多项式.你需要计算两个多项式相除的商Q和余R,其中R的阶数必须小于B的阶数. 输入格式: 输入分两行,每行给出一个非零多项式,先给出A,再给出B.每行的格式如下: N e[1] c[1] ... e[N] c[N]   其中N是该多项式非零项的个数,e[i]是第i个非零项的指数,c[i]是第i个非零项的系数.各项按照指数递减的顺序给出,保证所有指数是各不相同的非负整数,所有系数是非零整数,所有整数在整型范围…
/**  * 功能:给定数量不限的硬币.币值为25分,10分.5分.1分,计算n分有几种表示法. */ public static int makeChange(int n){ return makeChange(n,25); } /** * 递归的终止条件:全然简化为1分. * @param n * @param denom * @return */ public static int makeChange(int n,int denom){ int next_denom=0; switch(…
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这个问题我是在PAT大区赛题里遇见的.题目如下: 多项式A除以B(25 分) 这仍然是一道关于A/B的题,只不过A和B都换成了多项式.你需要计算两个多项式相除的商Q和余R,其中R的阶数必须小于B的阶数. 输入格式: 输入分两行,每行给出一个非零多项式,先给出A,再给出B.每行的格式如下: N e[1] c[1] ... e[N] c[N] 其中N是该多项式非零项的个数,e[i]是第i个非零项的指数,c[i]是第i个非零项的系数.各项按照指数递减的顺序给出,保证所有指数是各不相同的非负整数,所有系…
1009 Product of Polynomials (25 分) This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynom…
1009 Product of Polynomials (25)(25 分) This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a pol…
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A1009 Product of Polynomials (25)(25 分) This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a po…
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