题意 设 $$f_i = \left\{\begin{matrix}1 , \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  i < k\\ \prod_{j=1}^k f_{i-j}^{b_j} \ mod \ p, \ \ \ \ \ i > k\end{matrix}\right.$$ 求 $f_k$($1 \leq f_k < p$),使得 $f_m = n$.($1 \leq k\leq 100$) 分析 $f_n$ 可以表示…
题目链接:传送门 题目: Recursive sequence Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Submission(s): Problem Description Farmer John likes to play mathematics games with his N cows. Recently, they are attracted…
题目链接:https://vjudge.net/problem/HDU-5950 Recursive sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2727    Accepted Submission(s): 1226 Problem Description Farmer John likes to play mat…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5950 Farmer John likes to play mathematics games with his N cows. Recently, they are attracted by recursive sequences. In each turn, the cows would stand in a line, while John writes two positive numbers…
Recursive sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description Farmer John likes to play mathematics games with his N cows. Recently, they are attracted by recursive sequences. In each turn,…
Recursive sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 3832    Accepted Submission(s): 1662 Problem Description Farmer John likes to play mathematics games with his N cows. Recently…
题面 传送门 前置芝士 \(BSGS\) 什么?你不会\(BSGS\)?百度啊 原根 对于素数\(p\)和自然数\(a\),如果满足\(a^x\equiv 1\pmod{p}\)的最小的\(x\)为\(p-1\),那么\(a\)就是\(p\)的一个原根 离散对数 对于素数\(p\),以及\(p\)的一个原根\(g\),定义\(y\)为\(x\)的离散对数,当且仅当\(g^y\equiv x\pmod{p}\),记\(y\)为\(ind_g x\).不难发现原数和离散对数可以一一对应.也不难发现离…
题意:递推公式 Fn = Fn-1 + 2 * Fn-2 + n*n,让求 Fn; 析:很明显的矩阵快速幂,因为这个很像Fibonacci数列,所以我们考虑是矩阵,然后我们进行推公式,因为这样我们是无法进行运算的.好像有的思路,最后也没想出来,还是参考的大牛的博客 http://blog.csdn.net/spring371327/article/details/52973534 那是讲的很详细了,就不多说了,注意这个取模不是1e9+7,一开始忘了.. 代码如下: #pragma comment…
题目链接:CF1106F Lunar New Year and a Recursive Sequence 大意:已知\(f_1,f_2,\cdots,f_{k-1}\)和\(b_1,b_2,\cdots,b_k\),且有递推关系 \[ f_i=(\prod_{j=1}^kf_{i-j}^{b_j})\text%p \] 对于所有\(i>k\)均成立,给出\(f_n=m\),求\(f_k\),\(p=998244353\) 分析: 数论板子大集合 首先很显然有\(f_n=f_k^{q}\),于是考…
题目链接: Sequence Time Limit: 2000/1000 MS (Java/Others)     Memory Limit: 65536/65536 K (Java/Others) Problem Description Holion August will eat every thing he has found. Now there are many foods,but he does not want to eat all of them at once,so he fi…