水题 #include<cstdio> #include<cstring> #include<algorithm> using namespace std; +; int a[maxn][maxn]; int n,m; int main() { scanf("%d%d",&n,&m); ;i<=n;i++) ;j<=m;j++) scanf("%d",&a[i][j]); ; ;i<=n;…

B. Dinner with Emma 题目连接: http://www.codeforces.com/contest/616/problem/A Description Jack decides to invite Emma out for a dinner. Jack is a modest student, he doesn't want to go to an expensive restaurant. Emma is a girl with high taste, she prefer…

Content 翻译很明白,或者你也可以看我的简化版题意: 求一个 \(n\times m\) 的矩阵中每行的最小值的最大值. 数据范围:\(1\leqslant n,m\leqslant 100\). Solution 因为题意中有: 艾玛想最大限度地提高晚餐的成本,杰克想把它降到最低.而艾玛知道杰克的想法. 所以,艾玛肯定会选择一个使最低成本最高的一排.那么我们就直接模拟找到它就好了. Code 当然,开个 \(c\) 数组是多余的,你也可以直接每次读入一个变量,这样可以更省空间.但是,\(…

616A - Comparing Two Long Integers    20171121 直接暴力莽就好了...没什么好说的 #include<stdlib.h> #include<stdio.h> #include<math.h> #include<cstring> #include<iostream> #include<algorithm> using namespace std; string a,b;int sa,sb;…

Problem B:http://codeforces.com/contest/616/problem/B B. Dinner with Emma 题意:一对夫妻要去餐厅吃晚饭,Emma 想去最豪华(贵)的地方吃,Jack想去最朴素(便宜)的地方吃,于是两人用这个方法决定去哪吃:每个街道和大道的交叉口上有一个餐厅,给出n街道m大道,所以每一条街道上有m个餐厅,由Emma选街道,由Jack选餐馆,(反正Jack会选择Emma选的街道中最便宜的一家)输出最终决定去的餐馆价格. 思路:既然Jack要选…

Dinner with Emma CodeForces - 616B Jack decides to invite Emma out for a dinner. Jack is a modest student, he doesn't want to go to an expensive restaurant. Emma is a girl with high taste, she prefers elite places. Munhattan consists of n streets and…

Problem B:http://codeforces.com/contest/616/problem/B B. Dinner with Emma 题意:一对夫妻要去餐厅吃晚饭,Emma 想去最豪华(贵)的地方吃,Jack想去最朴素(便宜)的地方吃,于是两人用这个方法决定去哪吃:每个街道和大道的交叉口上有一个餐厅,给出n街道m大道,所以每一条街道上有m个餐厅,由Emma选街道,由Jack选餐馆,(反正Jack会选择Emma选的街道中最便宜的一家)输出最终决定去的餐馆价格. 思路:既然Jack要选…

Problem D. Dinner ProblemTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100342/attachments Description A group of k students from Cooking University living in the campus decided that each day of the semester one of them will p…

Fox Ciel is participating in a party in Prime Kingdom. There are n foxes there (include Fox Ciel). The i-th fox is ai years old. They will have dinner around some round tables. You want to distribute foxes such that: Each fox is sitting at some table…

题目链接:http://codeforces.com/problemset/problem/510/E 乍一看和那啥魔术球问题有点神似啊/XD 其实是不一样的. 解决这道问题的关键在于发现若是相邻的两个数的和是质数,那么他们必定是一奇一偶! 而且一个奇数旁边一定是两个偶数,一个偶数旁边一定是两个奇数(因为是一个大于$3$的环) 秒啊!这就变成了匹配模型. 源点向所有值为奇数的点连容量为$2$边,值为奇数的点向所有与它的和为质数的且值为偶数点连容量为$1$边,所有值为偶数的点向汇点连容量为$2$的…