第八题 class Solution { public: int myAtoi(string str) { ; ; ; while(str[i] == ' ')i++; if (str[i] == '-'|| str[i] == '+') { ; i++; } ') { if(sum>=INT_MAX) break; sum = sum * + str[i++] - '; } sum*=sign; if(sum>=INT_MAX)return INT_MAX; if(sum<=INT_M…

我现在在做一个叫<leetbook>的免费开源书项目,力求提供最易懂的中文思路,目前把解题思路都同步更新到gitbook上了,需要的同学可以去看看 书的地址:https://hk029.gitbooks.io/leetbook/ 008. String to Integer (atoi) [E] 题目 Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cas…

题目String to Integer (atoi)(难度Medium) 大意是找出给定字串开头部分的整型数值,忽略开头的空格,注意符号,对超出Integer的数做取边界值处理. 方案1 class Solution { fun myAtoi(str: String): Int { val maxInt = " val maxIntS = "+2147483647" val minIntS = "-2147483648" val lengthMI = ma…

String to Integer (atoi) time=272ms   accepted 需考虑各种可能出现的情况 public class Solution { public int atoi(String str) { int length=str.length(); long result=0; int flag=1; Boolean bFlag=false,bSpace=false,bNum=false; if(length<=0) return (int) result; else…

String to Integer (atoi) Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended f…

又是一道恶心的简单题. 一开始没想到这么多情况的,幸好LeetCode是个很人性化的oj,能让你知道你在哪个case上错了,否则一辈子都过不了. 考虑不周到只能一个个补了. 列举一下恶心的case //" 010" //" +004500" //" -0012a42" //"2147483648" //" b11228552307" //"18446744073709551617" //…

Problem: Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem…

题目描述: 把字符串转化为整数值 原文描述: Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for…

题目: Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be…

#-*- coding: UTF-8 -*-#需要考虑多种情况#以下几种是可以返回的数值#1.以0开头的字符串,如01201215#2.以正负号开头的字符串,如'+121215':'-1215489'#3.1和2和空格混合形式[顺序只能是正负号-0,空格位置可以随意]的:'+00121515'#4.正数小于2147483647,负数大于-2147483648的数字#其他的情况都是返回0,因此在判断 是把上述可能出现的情况列出来,其他的返回0#AC源码如下class Solution(object…