Algorithm | Binary Search】的更多相关文章

花了半天把二分查找的几种都写了一遍.验证了一下.二分查找的正确编写的关键就是,确保循环的初始.循环不变式能够保证一致. 可以先从循环里面确定循环不变式,然后再推导初始条件,最后根据循环不变式的内容推导出结果. 1. 普通的二分查找 第一版本: //first version int find(int arr[], int n, int target) { , r = n - ; while (l <= r) { ; if (arr[m] == target) return m; else if…
(binary search trees) which form the basis of modern databases and immutable data structures. Binary search works very much the way humans intuitively search for a name in a yellow pages directory (if you have ever seen one) or the dictionary. In thi…
Complexity: O(log(n)) Ref: Binary search algorithm or 二分搜索算法 Ref: C 版本 while 循环 C Language scripts by McDelfino: #include <stdio.h> #include <stdlib.h> int getIndex(int* arr, int length, int num); int main() { int arr[100]; for (int i = 0; i &…
js binary search algorithm js 二分查找算法 二分查找, 前置条件 存储在数组中 有序排列 理想条件: 数组是递增排列,数组中的元素互不相同; 重排 & 去重 顺序: 递增排列/递减排列; 重复: 数组中存在相同的元素; "use strict"; /** * * @author xgqfrms * @license MIT * @copyright xgqfrms * @created 2020-05-20 * @modified * * @des…
38. Search a 2D Matrix II https://www.lintcode.com/problem/search-a-2d-matrix-ii/description?_from=ladder&&fromId=1 这道题与二分法有什么关系呢? -把整个二维数组从对角线分成两半,从左下角开始,往右上角逼近. public class Solution { /** * @param matrix: A list of lists of integers * @param ta…
254. Drop Eggs https://www.lintcode.com/problem/drop-eggs/description?_from=ladder&&fromId=1 28. Search a 2D Matrix https://www.lintcode.com/problem/search-a-2d-matrix/description?_from=ladder&&fromId=1 思路1: 1. find the row index, the last…
The solution for the problem can be divided into three cases: case 1: if the delete node is leaf node, then we can simply remove it case 2: if the delete node is has single side or substree case 3: it has two children, then to keep it as a valid bina…
What is Binary Search Tree (BST) A binary tree in which for each node, value of all the nodes in left subtree is less or equal and value of all the nodes in right subtree is greater The idea: We can use set boundry for each node. We take C tree for e…
Let's say we are going to find out number of occurrences of a number in a sorted array using binary search in O(log n) time. For example the given array is: [1,1,3,5,5,5,5,5,9,11], the number 5 appears 5 times; the number 3 appears 1 time; 2 appears…
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. Top down 的解题方法: 1. 将LinkedList的值保存到一个数组中,转化成Convert Sorted Array to Binary Search Tree 来解决 时间复杂度为O(n), 空间复杂度为O(n) /** * Definition for singl…