Missing number Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) [Problem Description] There is a permutation without two numbers in it, and now you know what numbers the permutation has. Please find the two numbers…

1144 The Missing Number(20 分) Given N integers, you are supposed to find the smallest positive integer that is NOT in the given list. Input Specification: Each input file contains one test case. For each case, the first line gives a positive integer…

题意: 给一个含有n个整数的数组,数组中的元素应该是0-n.现在缺了其中某1个,找出缺少的那个整数? 思路: 0-n的总和是可以直接计算的,而缺少的那个就是sum减去数组的和. int missingNumber(vector<int>& nums) { ; ; i<nums.size(); i++) sum+=i+-nums[i]; return sum; } AC代码…

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example, Given nums = [0, 1, 3] return 2. Note: Your algorithm should run in linear runtime complexity. Could you implement it u…

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in linear runtime complexity. Could you implement it usi…

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in linear runtime complexity. Could you implement it usi…

Description: Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in linear runtime complexity. Could you imp…

题目 [题目传送门] 给定一个二进制数组, 计算其中最大连续1的个数. 示例 1: 输入: [1,1,0,1,1,1] 输出: 3 解释: 开头的两位和最后的三位都是连续1,所以最大连续1的个数是 3. 注意: 输入的数组只包含 0 和1. 输入数组的长度是正整数,且不超过 10,000. 来源:力扣(LeetCode) 解题 简单题我重拳出击:> 分析 题目给出了二进制数组,不是0就是1 题目中有连续要求所以对于对于1则是叠加次数,遇上0则是要求需要进行重置当前的计数,二最后返回是要求最大的连…

The Missing Number PAT-1144 #include<iostream> #include<cstring> #include<string> #include<algorithm> #include<cstdio> #include<sstream> #include<set> using namespace std; const int maxn=100005; set<int>se;…

今天的华师 Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example:Given binary tree [3,9,20,null,null,15,7], 3 / 9 20 / 15 7 return its bottom-up level…