590. N-ary Tree Postorder Traversal 自己没写出来   优秀代码: """ # Definition for a Node. class Node(object): def __init__(self, val, children): self.val = val self.children = children """ class Solution(object): def postorder(self,…

树的后序遍历. class Solution { public: vector<Node> Tree; void postTree(Node node) { for (auto n : node.children) { Node node; node = Node(n->val, n->children); postTree(node); } Tree.push_back(Node(node.val, node.children)); } vector<int> pos…

题目 1 class Solution { 2 public: 3 vector<int>ans; 4 vector<int> postorder(Node* root) { 5 dfs(root); 6 return ans; 7 } 8 void dfs(Node* root){ 9 if(root == NULL) return; 10 for(int i = 0;i < root->children.size();i++){ 11 dfs(root->ch…

590. N叉树的后序遍历 590. N-ary Tree Postorder Traversal 题目描述 给定一个 N 叉树,返回其节点值的后序遍历. LeetCode590. N-ary Tree Postorder Traversal 例如,给定一个 3 叉树: 返回其后序遍历: [5,6,3,2,4,1]. 说明: 递归法很简单,你可以使用迭代法完成此题吗? Java 实现 Iterative Solution import java.util.LinkedList; import j…