A. Calculating Function Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/486/problem/A Description For a positive integer n let's define a function f: f(n) = - 1 + 2 - 3 + .. + ( - 1)nn Your task is to calculate f(n) for a…
A. Calculating Function For a positive integer n let's define a function f: f(n) = - 1 + 2 - 3 + .. + ( - 1)nn Your task is to calculate f(n) for a given integer n. Input The single line contains the positive integer n (1 ≤ n ≤ 1015). Output Print…
Calculating Function time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output For a positive integer n let's define a function f: f(n) = - 1 + 2 - 3 + .. + ( - 1)nn Your task is to calculate f(n) f…
A. Calculating Function time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output For a positive integer n let's define a function f: f(n) = - 1 + 2 - 3 + .. + ( - 1)nn Your task is to calculate f(n…
Codeforces Round #277 (Div. 2) A. Calculating Function time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output For a positive integer n let's define a function f: f(n) = - 1 + 2 - 3 + .. + ( - 1)n…
门户:Codeforces Round #277 (Div. 2) 486A. Calculating Function 裸公式= = #include <cstdio> #include <cstring> #include <algorithm> using namespace std ; typedef long long LL ; LL n ; int main () { while ( ~scanf ( "%I64d" , &n )…
题目地址:http://codeforces.com/contest/486 A题.Calculating Function 奇偶性判断,简单推导公式. #include<cstdio> #include<iostream> using namespace std; int main() { long long n; cin>>n; ==) { cout<<(-)*((n-)/+)+n<<endl; } else cout<<((n-…
A. Calculating Function 水题,分奇数偶数处理一下就好了 #include<stdio.h> #include<iostream> using namespace std; int main() { long long n;scanf("%lld",&n); ==) printf("%lld\n",(n-1LL)/2LL - n); else printf("%lld\n",n/2LL); }…
