POJ 3126 - Prime Path - [线性筛+BFS]】的更多相关文章

题目链接:http://poj.org/problem?id=3126 题意: 给定两个四位素数 $a,b$,要求把 $a$ 变换到 $b$.变换的过程每次只能改动一个数,要保证每次变换出来的数都是一个没有前导零的四位素数. 要求每步得到的素数都不能重复,求从 $a$ 到 $b$ 最少需要变换多少步:如果无法达到则输出Impossible. 题解: 在BFS之前先用线性筛筛出 $10000$ 以内的素数,方便后面判断是否为素数. 剩下的就是从 $a$ 为起点,入队并标记已经出现过.每次队列非空就…
Prime Path The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-digit room numbers on their offices. — It is a matter of security to change such things every now a…
题目: http://poj.org/problem?id=3126 困得不行了,没想到敲完一遍直接就A了,16ms,debug环节都没进行.人品啊. #include <stdio.h> #include <string.h> #include <queue> using namespace std; ]; ]; int s, t; void prime_init() { memset(prime, , sizeof(prime)); prime[] = ; ; i…
题意:给两个四位素数a和b,求从a变换到b的最少次数,每次变换只能变换一个数字并且变换的过程必须也是素数. 思路:先打表求出四位长度的所有素数,然后利用BFS求解.从a状态入队,然后从个位往千位的顺序枚举下一个素数,入队,直到状态为b为止. #include <cstdio> #include <queue> #include <vector> #include <iostream> #include <cstring> #include <…
题目传送门 /* 题意:从一个数到另外一个数,每次改变一个数字,且每次是素数 BFS:先预处理1000到9999的素数,简单BFS一下.我没输出Impossible都AC,数据有点弱 */ /************************************************ Author :Running_Time Created Time :2015-8-2 15:46:57 File Name :POJ_3126.cpp ****************************…
  POJ 3126  Prime Path Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 16204   Accepted: 9153 Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change…
POJ 3126 Prime Path(素数路径) Time Limit: 1000MS    Memory Limit: 65536K Description - 题目描述 The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-digit room numbers on…
题目链接:http://poj.org/problem?id=3126 Prime Path Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 32036   Accepted: 17373 Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they…
Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-digit room numbers on their offices. — It is a matter of security to change such things every now…
Prime Path POJ - 3126 题意: 给出两个四位素数 a , b.然后从a开始,每次可以改变四位中的一位数字,变成 c,c 可以接着变,直到变成b为止.要求 c 必须是素数.求变换次数的最小值.(a,b,c都是四位数字,输入时没有前导零) 分析: 每次改变可以获得一个四位数c,然后如果c是素数并且之前没有出现过,那么我们把它放入队列即可. int f[10001]; int v[10001]; void init()//素数筛 { memset(f,0,sizeof f); fo…