Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Example: Input: [1,2,2] Output: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 这个题目思路…

Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Input: [1,2,2] Output: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 题意: 是的[leetcode…

Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. For example,If nums = [1,2,2], a solution is: [ [2], [1], [1,2,2], [2,2], [1,2…

Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: The solution set must not contain duplicate subsets. For example,If nums = [1,2,2], a solution is: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 题目标签:Arr…

Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a solution is:…

原题地址 跟Subsets(参见这篇文章)类似. 但因为有重复元素,所以要考虑去重问题. 什么情况下会出现重复呢?比如S = {5, 5, 5},如果要选1个5,一共有C(3,1)=3种选法,即100, 010, 001,这三种情况在集合的角度看是重复的情况.如果要选2个5,共有C(3,2)=3种选法,即011, 101, 110,这三种情况在集合的角度上看也是重复的. 本质在于,如果要在重复出现的数字当中选择若干个,则只能保留一种取法,其他的都是重复.即,这些重复数字对应的二进制位当中,只能保…

Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, If nums = [1,2,2], a soluti…

第一题是输入数组的数值不相同,第二题是输入数组的数值有相同的值,第二题在第一题的基础上需要过滤掉那些相同的数值. level代表的是需要进行选择的数值的位置. 78. Subsets 错误解法: class Solution { public: vector<vector<int>> subsets(vector<int>& nums) { vector<vector<int> > result; if(nums.empty()) ret…

Subsets II Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a so…

python solution 123456789101112131415161718192021222324252627 class (object): def subsetsWithDup(self, nums): """ :type nums: List[int] :rtype: List[List[int]] """ """ 思路整理:DFS recursion 1)对nums进行排序以避免nums中重复元素…

Subsets II Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,2]…

题目: Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,2], a sol…

78. Subsets Given a set of distinct integers, nums, return all possible subsets. Note: The solution set must not contain duplicate subsets. For example, If nums = [,,], a solution is: [ [], [], [], [,,], [,], [,], [,], [] ] class Solution { public: v…

Subsets II 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/subsets-ii/description/ Description Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain du…

Subsets II Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a so…

Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, If nums = [1,2,2], a soluti…

90. 子集 II 给定一个可能包含重复元素的整数数组 nums,返回该数组所有可能的子集(幂集). 说明:解集不能包含重复的子集. 示例: 输入: [1,2,2] 输出: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] PS: 先进行排序,保证重复元素挨在一起 记录每次遍历生成的新序列的长度,这里用left表示每次遍历的开始位置,right结束位置,len表示长度 根据与前面元素是否重复,来决定left的取值,也就是开始遍历的位置 其实和子集1还是差不多的 cl…

90. 子集 II 78. 子集题的扩展,其中的元素可能会出现重复了 我们仍沿用78题的代码,稍作改动即可: 此时需要对nums先排个序,方便我们后面跳过选取相同的子集. 跳过选取相同的子集.当选取完第i个数时,如果后面的数,和当前数相同,就跳过,不必对其进行递归了. class Solution { private void dfs(int n, int k, int last, int[] nums, List<Integer> cur, List<List<Integer&g…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: The solution set must not contain duplicate subsets. F…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 回溯法 日期 题目地址:https://leetcode.com/problems/subsets-ii/description/ 题目描述 Given a collection of integers that might contain duplicates, nums, return all possible subsets (the po…

题目描述 给定一个可能包含重复元素的整数数组 nums,返回该数组所有可能的子集(幂集). 说明:解集不能包含重复的子集. 示例: 输入: [1,2,2] 输出: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 解题思路 利用回溯的思想,对于每个元素分为两种情况:不添加到子集或者添加到子集.注意因为有重复元素,所以先对整个数组排序使得重复元素到一起,若遇到重复元素,则单独处理,针对每种可能的组合情况添加或不添加到子集中. 代码 class Solution { p…

Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,2], a solutio…

深度优先搜索算法(depth first search),是一个典型的图论算法.所遵循的搜索策略是尽可能“深”地去搜索一个图. 算法思想是: 对于新发现的顶点v,如果它有以点v为起点的未探测的边,则沿此边继续探测下去.当顶点v的所有边都已被探寻结束,则回溯到到达点v的先辈节点.以相同方法一直回溯到源节点为止.如果图中还有未被发现的顶点,则选择其中一个作为源顶点,重复以上的过程.最后的结果是一些不相交的深度优先树. leetCode中的应用: Given a collection of integ…

1. Given a set of distinct integers, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,3], a solution is: [ [3], [1], [2], [1…

Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a solution is:…

给定一个数组,返回所有的非重复的可能.例如给定 If S = [1,2,2], a solution is: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 其实这题类似的有Combination和Subsets.有兴趣的可以看看之前的解题方法.那大概是第70题左右,十天以前做的吧.记得当时用了回溯法.现在这个还是要用到回溯.只是加了判断有重复的子集怎么办. 在回溯的过称中,记录一种可能后就把最后一个pop掉,然后回溯上一个的时候判断是不是和之前判断过的相等了.用…

Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: The solution set must not contain duplicate subsets. For example, If nums = [1,2,2], a solution is: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 有重复值的序列…

题目: Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a solution…

Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Example: Input: [1,2,2] Output: [ [2], [1], [1,2,2], [2,2], [1,2], [] ]   clas…

Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Example: Input: [1,2,2] Output: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] Soluti…