SPOJ - GSS3 Can you answer these queries III Description You are given a sequence A of N (N <= 50000) integers between -10000 and 10000. On this sequence you have to apply M (M <= 50000) operations: modify the i-th element in the sequence or for giv…

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Time Limit: 1000MS   Memory Limit: 1572864KB   64bit IO Format: %lld & %llu Description Being a completist and a simplist, kid Yang Zhe cannot solve but get Wrong Answer from most of the OI problems. And he refuse to write two program of same kind at…

1.VS2013使用EntityFrame问题解决办法 解决办法参照博客http://pinter.org/?p=2374 使用到EntityFrame的项目配置文件修改如下: 项目中凡是使用到DbContext类或者说直接与数据库通讯的类的构造函数添加如下代码 2.Sql Server实例登录问题 问题:error 'Named Pipes Provider, error 40 - Could not open a connection to' SQL Server' Answer:参考htt…

著作权归作者所有.商业转载请联系作者获得授权,非商业转载请注明出处.作者:梁川链接:https://www.zhihu.com/question/27606493/answer/37447829来源:知乎 1.支付平台有自己的一套客户/账户/账务体系,用于记录各个客户/商户的基本信息.账户信息.账务信息.基本信息包括实名认证信息.联系方式等等信息.账户信息比较重要的属性是账户资金/余额,此处的账户资金实际上只是虚拟账户的资金信息,并非实际的资金,实际的资金存放在支付平台在银行设立的银行账户上.关…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=4027 Can you answer these queries? Description Problem Description A lot of battleships of evil are arranged in a line before the battle. Our commander decides to use our secret weapon to eliminate the b…

GSS7 Can you answer these queries IV 题目:给出一个数列,原数列和值不超过1e18,有两种操作: 0 x y:修改区间[x,y]所有数开方后向下调整至最近的整数 1 x y:询问区间[x,y]的和 分析: 昨天初看时没什么想法,于是留了个坑.终于在今天补上了. 既然给出了1e18这个条件,那么有什么用呢?于是想到了今年多校一题线段树区间操作时,根据一些性质能直接下沉到每个节点,这里可以吗?考虑1e18开方6次就下降到1了,因此每个节点最多被修改6次.于是我们每…

GSS7Can you answer these queries VII 给出一棵树,树的节点有权值,有两种操作: 1.询问节点x,y的路径上最大子段和,可以为空 2.把节点x,y的路径上所有节点的权值置为c 分析: 修改树路径的信息,可以考虑一下树链剖分.动态树. 这题可以用树链剖分的方式来做,不会的可以看看这篇 树链剖分---模板.其实树链剖分不难理解,一小时左右就能学会了. 对于在一段区间的最大子段和问题,可以参考GSS1 spoj 1043 Can you answer these qu…

GSS6 Can you answer these queries VI 给出一个数列,有以下四种操作: I x y: 在位置x插入y.D x  : 删除位置x上的元素.R x y: 把位置x用y取替.Q x y: 输出区间[x,y]的最大字段和. 分析: 其实这题是BZOJ 1500 [NOI2005]维修数列这题的简化版. 使用splay来做非常简单. 我的做法增加一个虚拟节点在数列的最开始处,增加两个虚拟节点在最后,这是为了方便在数列最后插入的操作. splay网上的资料比较多,其实spl…

gss5 Can you answer these queries V 给出数列a1...an,询问时给出: Query(x1,y1,x2,y2) = Max { A[i]+A[i+1]+...+A[j] ; x1 <= i <= y1 , x2 j <= y2 and x1 <= x2 , y1 <= y2 } 分析: 其实画个图分类讨论一下之后,跟gss1基本一样... 注意到x1<=x2 , y1<=y2. 所以大致可以分为: 1.y1<x2: 直接计…

gss2调了一下午,至今还在wa... 我的做法是:对于询问按右区间排序,利用splay记录最右的位置.对于重复出现的,在splay中删掉之前出现的位置所在的节点,然后在splay中插入新的节点.对于没有出现过的,直接插入.询问时直接统计区间的最大子段和. gss2没能调出bug,所以看了一下以下的gss3,发现跟gss1基本一样.直接上代码 以上的做法是错的,对于这种数据就过不了.姿势不对,囧 44 -2 3 -211 4 GSS Can you answer these queries II…

今天下午不知道要做什么,那就把gss系列的线段树刷一下吧. Can you answer these queries I 题目:给出一个数列,询问区间[l,r]的最大子段和 分析: 线段树简单区间操作. 线段树中记录lx,rx,mx,分别表示:最大前驱连续和,最大后继连续和,区间最大子段和. 在合并时时只需要合并两个区间即可,具体可以看代码的Union. 从队友jingo那里学到了这种合并的写法,发现比网上大部分代码简单很多. #include <set> #include <map&g…

This is a new series of sharing core Java interview question and answer on Finance domain and mostly on big Investment bank.Many of these Java interview questions are asked on JP Morgan, Morgan Stanley, Barclays or Goldman Sachs. Banks mostly asked c…

Wrong Answer 思路: 1.先枚举4的全排列,即球赛的所有可能结果,一共4!=24种情况 2.对于每种情况,DFS 未确定的比赛 的结果,判断这种情况是否可达. 剪枝: 1.对于每种全排列,只需要找到一种满足这个全排列的情况即可,如果有一种情况满足,则不必再枚举其他可能. 2.因为在每种情况下,球队之间的排名已经确定了,所以在DFS的过程中,凡是不满足此排名的情况统统可以剪掉. 这样就可以少很多情况,即使在n=0的情况下也跑出了不错的效率,但是它Wrong Answer on test…

题解: 从没见过这么XXX的线段树啊... T_T 我们考虑离线做,按1-n一个一个插入,并且维护区间[ j,i](i为当前插入的数)j<i的最优值. 但这个最优值!!! 我们要保存历史的最优值,以及当前的最优值!!!还有lazy!!!也得分历史和现在!!T_T 怎么搞!!! inline void update(int k,int z1,int z2) { t[k].tag[]=max(t[k].tag[],t[k].tag[]+z2); t[k].tag[]+=z1; t[k].mx[]=m…

Can you answer these queries II Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 https://www.spoj.com/problems/GSS2/ Description Being a completist and a simplist, kid Yang Zhe cannot solve but get Wrong Answer from most of the OI problems. And he refuse…

Given a tree with N ( N<=100000 ) nodes. Each node has a interger value x_i ( |x_i|<=10000 ). You have to apply Q ( Q<=100000 ) operations: 1. 1 a b : answer the maximum contiguous sum (maybe empty,will always larger than or equal to 0 ) from the…

2482: [Spoj1557] Can you answer these queries II Time Limit: 20 Sec  Memory Limit: 128 MBSubmit: 145  Solved: 76[Submit][Status][Discuss] Description 给定n个元素的序列. 给出m个询问:求l[i]~r[i]的最大子段和(可选空子段). 这个最大子段和有点特殊:一个数字在一段中出现了两次只算一次. 比如:1,2,3,2,2,2出现了3次,但只算一次,…

4487. Can you answer these queries VI Problem code: GSS6 Given a sequence A of N (N <= 100000) integers, you have to apply Q (Q <= 100000) operations: Insert, delete, replace an element, find the maximum contiguous(non empty) sum in a given interval…

1557. Can you answer these queries II Problem code: GSS2 Being a completist and a simplist, kid Yang Zhe cannot solve but get Wrong Answer from most of the OI problems. And he refuse to write two program of same kind at all. So he always failes in co…

GSS3 - Can you answer these queries III You are given a sequence A of N (N <= 50000) integers between -10000 and 10000. On this sequence you have to apply M (M <= 50000) operations: modify the i-th element in the sequence or for given x y print max{…

Unable to find a suitable version for underscore, please choose one by typing on e of the numbers below: ) underscore# - and is required by mario nette# ) underscore#>= and is required by backbone#. ) underscore#^ and is required by backgrid#0.3 . )…

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机器学习基石 2 Learning to Answer Yes/No Perceptron Hypothesis Set 对于一个线性可分的二分类问题,我们可以采用感知器 (Perceptron)这种假设集. 这种模型可以用下面的表达式表示出来: 其中不同的向量 \(w\) 代表了不同的假设函数 \(h(x)\),我们的目标是使用一些算法调整 \(w\) 的值,使得假设函数 \(h(x)\) 与我们要预测的函数 \(f(x)\) 尽可能的接近. 我们的想法是:如果 \(h(x)\) 与 \(f(…

毕业设计跟的导师是研究计算机理论的,花了三个月学习符号逻辑,试图优化一个回答集程序的求解器(Answer set solver).比起眼花缭乱的前端框架和热闹的社区讨论,符号逻辑就是一个挺小众的数学领域.一讲到逻辑程序就会涉及一大堆的概念 ,伴随一大堆数理逻辑的符号,令有兴趣的新手望而却步.此篇博文可以说是导师的博士论文的一篇读后感,一篇回答集编程的发展史,一篇回答集程序入门简介.详见<提高ASP效率的若干途径及在服务机器人上的应用>. 1.人工智能学派 一些传统人工智能的研究者认为,(人工)…

A lot of battleships of evil are arranged in a line before the battle. Our commander decides to use our secret weapon to eliminate the battleships. Each of the battleships can be marked a value of endurance. For every attack of our secret weapon, it…

Can you answer these queries? Time Limit:2000MS     Memory Limit:65768KB     64bit IO Format:%I64d & %I64u Submit Status Description A lot of battleships of evil are arranged in a line before the battle. Our commander decides to use our secret weapon…

GSS4 - Can you answer these queries IV(线段树懒操作) 标签: 线段树 题目链接 Description recursion有一个正整数序列a[n].现在recursion有m次操作: (A)对于给定的x,y,使所有满足下标i在x,y之间的数a[i]开方下取整. (B)对于给定的x,y,输出满足下标i在x,y之间的数a[i]的和. 这么简单的题,recursion当然会做啦,但是为了维持她的傲娇属性,她决定考考你. Input 包含多组数据,文件以EOF结尾…

SPOJ GSS1_Can you answer these queries I(线段树区间合并) 标签(空格分隔): 线段树区间合并 题目链接 GSS1 - Can you answer these queries I You are given a sequence A1, A[2], ..., A[N] . ( |A[i]| ≤ 15007 , 1 ≤ N ≤ 50000 ). A query is defined as follows: Query(x,y) = Max { a[i]+a…

Warm Up Answer: foo Point(3) Anchors Answer: k$ Point(2) It never ends $ not allowed Answer: fu\b Point(4) 或者 u\b Ranges Answer:[a-f][a-f][a-f][a-f] Point(20) Backrefs Answer: (...).*\1 Point(9) Abba Answer: ^(?!.*(.)(.)\2\1) Point(17) A man, a plan…