链接: http://poj.org/problem?id=1258 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=82831#problem/I Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 45751   Accepted: 18835 Description Farmer John has been elected mayor of his town!…

#include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #define MAX 102 void read(); using namespace std; int map[MAX][MAX],best[MAX],n; bool visit[MAX]; int main() { //freopen("in.txt","r",stdin…

poj 1251  && hdu 1301 Sample Input 9 //n 结点数A 2 B 12 I 25B 3 C 10 H 40 I 8C 2 D 18 G 55D 1 E 44E 2 F 60 G 38F 0G 1 H 35H 1 I 353A 2 B 10 C 40B 1 C 200Sample Output 21630 prim算法 # include <iostream> # include <cstdio> # include <cstr…

#include <iostream>// poj 1258 10.1.5.253 1505 using namespace std; #define N 105 // 顶点的最大个数 (多写 int a[N][N],low[N],n,ans; int min(int x,int y) { return x<y?x:y; } void prim(int u0) { int i,j,m,k; ans=0; // for (i=1;i<n;i++) low[i]=a[u0][i]; /…

POJ 1258 Agri-Net http://poj.org/problem?id=1258 水题. 题目就是让你求MST,连矩阵都给你了. prim版 #include<cstdio> const int MAXN=101; const int INF=100000+10; int map[MAXN][MAXN]; int dis[MAXN]; int n; void prim() { bool vis[MAXN]={0}; for(int i=0;i<=n;i++) dis[i]…

http://poj.org/problem?id=1258 FJ为了竞选市长,承诺为这个地区的所有农场联网,为了减少花费,希望所需光纤越少越好,给定每两个农场的花费,求出最小花费. 最小生成树. #include <cstdio> #include <algorithm> using namespace std; ; <<; int cost[maxn][maxn]; int mincost[maxn]; bool used[maxn]; int n; int pri…

POJ 最小生成树模板 Kruskal算法 #include<iostream> #include<algorithm> #include<stdio.h> #include<string.h> #include<ctype.h> #include<stdlib.h> #include<limits.h> #include<math.h> #include<queue> #include<st…

23333333333 完全是道水题.因为是偶自己读懂自己做出来的..T_T.prim的模板题水过. DESCRIPTION:John竞选的时候许诺会给村子连网.现在给你任意两个村子之间的距离.让你求任意两个村庄是连通的所需要的网线.就是求最小生成树的权值. 附代码: #include<stdio.h>#include<iostream>#include<string.h>#include<string>#include<algorithm>#d…

点击打开链接 Agri-Net Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 33733   Accepted: 13539 Description Farmer John has been elected mayor of his town! One of his campaign promises was to bring internet connectivity to all farms in the area.…

用的是prim算法. 我用vector数组,每次求最小的dis时,不需要遍历所有的点,只需要遍历之前加入到vector数组中的点(即dis[v]!=INF的点).但其实时间也差不多,和遍历所有的点的方法都是16ms... #include <iostream> #include <algorithm> #include <string.h> #include <stdio.h> #include <string> #include <que…