美素数 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others) Total Submission(s): 853 Accepted Submission(s): 329 Problem Description 小明对数的研究比较热爱,一谈到数,脑子里就涌现出好多数的问题,今天,小明想考考你对素数的认识. 问题是这样的:一个十进制数,如果是素数,而且它的各位数字和也是素数,则称之为…
美素数 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others) Total Submission(s): 4482 Accepted Submission(s): 1524 Problem Description 小明对数的研究比較热爱,一谈到数.脑子里就涌现出好多数的问题,今天.小明想考考你对素数的认识. 问题是这种:一个十进制数.假设是素数,并且它的各位数字和也是素数,则称之…
美素数 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 4291 Accepted Submission(s): 1476 Problem Description 小明对数的研究比较热爱,一谈到数,脑子里就涌现出好多数的问题,今天,小明想考考你对素数的认识. 问题是这样的:一个十进制数,如果是素数,而且它的各位数字和也是素数,则称之…
另类打表:将从1到n的满足美素数条件的数目赋值给prime[n],这样最后仅仅须要用prime[L]减去prime[R-1]就可以: 美素数 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others) Total Submission(s): 2332 Accepted Submission(s): 811 Problem Description 小明对数的研究比較热爱,一谈到数,脑…
Lweb and String Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 261 Accepted Submission(s): 174 Problem Description Lweb has a string S. Oneday, he decided to transform this string to a new s…
找素数本来是很简单的问题,但当数据变大时,用朴素思想来找素数想必是会超时的,所以用素数筛法. 素数筛法 打表伪代码(用prime数组保存区间内的所有素数): void isPrime() vis[]数组清零://vis[]数组用于标记是否已被检验过 prime[]数组全赋初值false://prime[]数组从下标0开始记录素数 for i = 2 to MAXN (i++) if 数i未被检验过 prime[tot++]=i; for j = i*i to MAXN (j+=i) //j是i的…
题目链接 F(N) Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4579 Accepted Submission(s): 1610 Problem Description Giving the N, can you tell me the answer of F(N)? Input Each test case contains a si…
Dertouzos Time Limit: 7000/3500 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1861 Accepted Submission(s): 584 Problem Description A positive proper divisor is a positive divisor of a number n, excluding n its…
简单的素数问题 HDOJ4548_美素数 #include<stdio.h> #include<stdlib.h> #include<math.h> #include<string.h> bool num[1000005]={false,false,true};//初始化1不是素数,2为素数 int suShu[1000005]={0};//存储当前数字以内的美素数个数 int main() { //求解N以内的所有素数序列 int sum=0; int i…